Ask question

Ask question

All categories

3 years ago

5

Which term defines the amount of mechanical work an engine can do per unit of heat energy it uses?

1 answer:

hammer [34]3 years ago

6 0

Answer:

d

Explanation:

is the because that's the amount of work in making machine can do producing heat

You might be interested in

prove that the heat transfer at the constant pressure is given by the enthalpy change during the process

mihalych1998 [28]

Answer:

at constant pressure, the heat flow for any process is equal to the change in the internal energy of the system plus the PV work done. Comparing the previous two equations shows that at constant pressure, the change in the enthalpy of a system is equal to the heat flow: ΔH=qp.

Explanation:

Give brainliest

5 0

3 years ago

State 3 advantages and 3 disadvantages of unit rate contract

Zinaida [17]

6 would be the answer

7 0

3 years ago

List the thermal conductivities of five

ICE Princess25 [194]

Answer:

Sorry I don't understand

Explanation:

8 0

3 years ago

The design for a new cementless hip implant is to be studied using an instrumented implant and a fixed simulated femur.

OlgaM077 [116]

Answer:

a) the velocity of the implant immediately after impact is 20 m/s

b) the average resistance of the implant is 40000 N

Explanation:

a) The impulse momentum is:

mv1 + ∑Imp(1---->2) = mv2

According the exercise:

v1=0

∑Imp(1---->2) = F(t2-t1)

m=0.2 kg

Replacing:

$0+F(t_{2} -t_{1} )=0.2v_{2}$

if F=2 kN and t2-t1=2x10^-3 s. Replacing

$0+2x10^{-3} (2x10^{-3} )=0.2v_{2} \\v_{2} =\frac{4}{0.2} =20m/s$

b) Work and energy in the system is:

T2 - U(2----->3) = T3

where T2 and T3 are the kinetic energy and U(2----->3) is the work.

$T_{2} =\frac{1}{2} mv_{2}^{2} \\T_{3} =0\\U_{2---3} =-F_{res} x$

Replacing:

$\frac{1}{2} *0.2*20^{2} -F_{res} *0.001=0\\F_{res} =40000N$

3 0

3 years ago

If 1 uF capacitor is fully charged with 120 V across it, how much energy is stored in it? (a) 7.2 kJ (b) 7.2 mJ (c) 0.12 mJ (d)

jeyben [28]

Answer:

(b) 7.2 mJ

Explanation:

ENERGY STORED IN CAPACITOR: the energy is stored in capacitor in electric field

which can be calculated by expressions

E= $\frac{1}{2}$ c $v{^2}$

= $\frac{1}{2}$ $10^{-6}$ $120^{2}$

=7200× $10^{-6}$ J

= 7.2× $10^{-3}$ J

=7.2 mJ

4 0

3 years ago