Answer:
B. No solution
Step-by-step explanation:
Answer:
0
Step-by-step explanation:
Plug p and q in
1+-1/2
0/2
0
If this helps please mark as brainliest
Answer:
P(A∩B) = 0.522
Step-by-step explanation:
Let's call A the event that a puppy is adopted and B the probability that a puppy live 7 or more years
So, the probability P(A∩B) that a randomly selected puppy in the shelter will get adopted and live 7 or more years is:
P(A∩B) = P(A)*P(B/A)
Because A and B are not independents.
Then, the probability P(A) that a puppy is adopted is 58% and the probability P(B/A) that a puppy live 7 or more years given that the puppy is adopted is 90%.
Finally, replacing the values, we get:
P(A∩B) = 0.58*0.9 = 0.522
It means that the 52.2% of the puppies are adopted and live 7 or more years.
Using transformations and congruency concepts, it is found that with these following transformations, the triangles will be congruent.
- A reflection, then a translation.
-
A rotation, then a reflection.
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- Two triangles are congruent if they have the <u>same lengths</u> of the sides and the <u>same angles.</u>
- In a reflection, there is a rule that changes the <u>coordinates (x,y)</u>, but does <u>not </u>change <u>the lengths</u> of the sides of the triangles, thus they will still be congruent.
- A <u>reflection is also a special case of rotation</u>, thus, in a rotation, the triangles are also congruent.
- A translation is also similar to a reflection, using rules to shift the triangle up, down, left or right according to it's coordinates, not changing the sides or angles, thus congruent.
- In a dilation, the <u>lengths of the sides are changed</u>, thus, the triangles will not be congruent.
--------------------------
Thus, from the bullet points above, the correct options are:
- A reflection, then a translation.
- A rotation, then a reflection.
A similar problem is given at brainly.com/question/24267298
Answer:
No problem ;)
Step-by-step explanation:
1/4: 0.25
2/4:0.50
3/4: 0.75
4/4(1): 1
<em>Hope </em><em>this</em><em> </em><em>helps </em><em>you!</em>