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scZoUnD [109]
3 years ago
10

A current of 4 ampere flows in a wire of resistivity 60 ohm calculate power

Physics
2 answers:
Reil [10]3 years ago
7 0
The answer is 240 Volt
ohaa [14]3 years ago
4 0
Plz see the attachment....

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At each corner of a square of side l there are point charges of magnitude Q, 2Q, 3Q, and 4Q.What is the magnitude and direction
bogdanovich [222]

Answer:

magnitude of force on charge 2Q  = \frac{KQ^{2} }{I^{2} }

Direction of force on charge = 61 ⁰

Explanation:

The magnitude on the force on the charge can be evaluated by finding the net force acting on the charge 2Q  i.e x-component of the net force and the y-component of the net force

║F║ = \sqrt{f_{x}^{2} + f_{y}^{2}    }  =  after considering the forces coming from Q, 3Q and 4Q AND APPLYING COULOMBS LAW

magnitude of force acting on 2Q = \frac{KQ^{2} }{I^{2} }

The direction of the force on charge 2Q is calculated as

tan ∅ = \frac{f_{y} }{f_{x} } = 1.8284

therefore ∅ = tan^{-1}  1.8284

= 61⁰

3 0
3 years ago
Which of these galaxies would you most likely find at the center of a large cluster of galaxies?
Arada [10]

Answer:

b. a large elliptical galaxy

Explanation:

In elliptical galaxies the stars are grouped in an elliptical shape, it has a low quantity of gas and dust in comparison to spiral galaxies, and its stars belong to an old population, there is not new stellar formation in it.

The stars orbit in a messy way which made to believe that they form from the merger of galaxies.

They are also really massive (around 10^{4} solar masses).

The most massive and luminous can be found in the center of cluster of galaxies.  

4 0
3 years ago
How far will a you travel if you run for 10 minutes at 2 m/sec?
ruslelena [56]
You must first convert minutes to seconds so 10*60=600

Then multiply the number of seconds by the speed so 600*2=1200 m
4 0
3 years ago
Read 2 more answers
An object, whose mass is 0.660 kg, is attached to a spring with a force constant of 132 N/m. The object rests upon a frictionles
Arada [10]

Answer:

See below

Explanation:

a)  Spring force at release =  k * d = 132 N/m * .120 m = 15.84 N

b) F = ma

   15.84 = (.660 kg)(a)     a = 24 m/s^2

c) Toward the left ....the object is accelerated to the left

7 0
1 year ago
Two objects each moving with speed v travel in opposite directions along a straight line passing through both their centers. The
Tpy6a [65]

Answer:

\dfrac{1}{16}

\dfrac{5}{3}

Explanation:

m_1 = Mass of first object

m_2 = Mass of second object

v = Speed of both objects

\dfrac{v}{4} = Combined velocity

The ratio of final kinetic energy to initial kinetic energy will be

\dfrac{K_f}{K_i}=\dfrac{\dfrac{1}{2}(m_1+m_2)(\dfrac{v}{4})^2}{\dfrac{1}{2}(m_1v^2+m_2v^2)} \\\Rightarrow \dfrac{K_f}{K_i}=\dfrac{(m_1+m_2)\dfrac{v^2}{16}}{m_1v^2+m_2v^2}\\\Rightarrow \dfrac{K_f}{K_i}=\dfrac{(m_1+m_2)\dfrac{1}{16}}{m_1+m_2}\\\Rightarrow \dfrac{K_f}{K_i}=\dfrac{1}{16}

The ratio is \dfrac{1}{16}

As the linear momentum is conserved

m_1v-m_2v=(m_1+m_2)\dfrac{v}{4}\\\Rightarrow m_1-m_2=(m_1+m_2)\dfrac{1}{4}

Divide by m_2 on both sides

\dfrac{m_1}{m_2}-1=\dfrac{m_1}{4m_2}+\dfrac{1}{4}\\\Rightarrow \dfrac{m_1}{m_2}-\dfrac{m_1}{4m_2}=\dfrac{1}{4}+1\\\Rightarrow \dfrac{3m_1}{4m_2}=\dfrac{5}{4}\\\Rightarrow \dfrac{m_1}{m_2}=\dfrac{5\times 4}{3\times 4}\\\Rightarrow \dfrac{m_1}{m_2}=\dfrac{5}{3}

The ratio of mass is \dfrac{5}{3}

6 0
3 years ago
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