Answer:
10.08 L.
Explanation:
- If we assume that CO₂ gas behaves ideally at STP (standard T(0.0 °C) and P(1.0 atm)):
<em>It is known that 1.0 mole of ideal gas occupies 22.4 L at STP conditions.</em>
<em></em>
<u><em>Using cross multiplication:</em></u>
1.0 mole of CO₂ gas occupies → 22.4 L.
0.45 mole of CO₂ gas occupies → ??? L.
<em>∴ The volume occupied by 0.45 mole of CO₂ gas </em>= (0.45 mol)(22.4 L)/(1.0 mol) = <em>10.08 L.</em>
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It would be 5.0 more in i did this
Answer:
A.All Mixtures Are Made Up Of Solutions
Explanation:
