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ioda
3 years ago
13

What is the chemical name of the compound. Cu2CO3

Chemistry
1 answer:
Naya [18.7K]3 years ago
5 0
The name of that is Copper.
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The<br> is the continuous movement of water between the<br> atmosphere, the land and the oceans.?
vekshin1

Answer:

hydrologic cycle

Explanation:

7 0
3 years ago
Unlike gases, the behavior of liquids and solids cannot be described by a set of laws that can be applied regardless of the iden
Tresset [83]

Answer:

a. True

Explanation:

The gases that we study are governed by different laws of physics. Gases behaves according to some given set of laws like the Universal gas laws, Boyles law, Charles law, Gay Lussac's law and many more.

But we do not see a definite pattern or rule when we study solids or liquids. The behavior of the solids and liquids are not described by the set of laws which are applied regardless of the identity of the substance.

6 0
3 years ago
The side chain of histidine has a pKa of about 6. What percent of histidine side chains would be deprotonated at pH 7.5
Setler [38]

The percent of histidine side chains would be deprotonated at pH 7.5  is 5.77 %.

<h3>What is pKa?</h3>

The term pKa refers to the negative logarithm of the acid dissociation constant (Ka). The pH is the negative logarithm of the hydrogen ion concentration.

Hence;

Ka = Antilog (-6) =1 * 10^-6

[H^+] = Antilog (-7.5) = 3 * 10^-8 M

We now have to use the formula;

α = \sqrt{} \frac{Ka}{[H^+] }

α = \sqrt{} \frac{ 1 *10^-6}{3 *10^-8  }

α = 5.77 %

Hence, the percent of histidine side chains would be deprotonated at pH 7.5  is 5.77 %.

Learn more about percent dissociation: brainly.com/question/12273293

3 0
3 years ago
A radioactive isotope of potassium (k) has a half-life of 20 minutes. if a 43 gram sample of this isotope is allowed to decay fo
Ksenya-84 [330]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 43 g

m (final mass after time T) = ? (in g)

x (number of periods elapsed) = ?

P (Half-life) = 20 minutes

T (Elapsed time for sample reduction) = 80 minutes

Let's find the number of periods elapsed (x), let us see:

T = x*P

80 = x*20

80 = 20\:x

20\:x = 80

x = \dfrac{80}{20}

\boxed{x = 4}

Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:

m =  \dfrac{m_o}{2^x}

m =  \dfrac{43}{2^{4}}

m = \dfrac{43}{16}

\boxed{\boxed{m = 2.6875\:g}}\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

8 0
4 years ago
What is the pressure, in atm, of 24.5 L of ideal gas at 247.8 K if there are 1.8 moles present?
Flura [38]

Answer:

p = 1.5 atm

Explanation:

pV = nRT

p = nRT/V = [1.8 mol×(0.082 atm L/mol K)×247.8 K]/24.5 L

p = 1.5 atm

8 0
3 years ago
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