3 years ago

Pls help meh Kdjdjeidjndiejdididjdjjdidjdjdiejd

Physics

2 answers:

Nadya [2.5K]3 years ago

6 0

Answer:

i think b

Explanation:

i'm not sure

REY [17]3 years ago

5 0

Answer:

I think both pure substance and an element .

hope it is helpful to you ☺️☺️

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You are exploring a distant planet. When your spaceship is in a circular orbit at a distance of 630 km above the planet's surfac

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Answer:

$R = 24.3 m$

Explanation:

As we know that the orbital speed is given as

$v = \sqrt{\frac{GM}{R + h}}$

here we know that

v = 5500 m/s

$R = 4.48 \times 10^6 m$

$h = 630 km$

now we have

$5500 = \sqrt{\frac{(6.6 \times 10^{-11})M}{4.48 \times 10^6 + 6.30\times 10^5}}$

$M = 2.34 \times 10^24 kg$

now acceleration due to gravity of planet is given as

$a = \frac{GM}{R^2}$

$a = \frac{(6.6 \times 10^{-11})(2.34 \times 10^{24})}{(4.48\times 10^6)^2}$

$a = 7.7 m/s^2$

now range of the projectile on the surface of planet is given as

$R = \frac{v^2 sin2\theta}{g}$

$R = \frac{14.6^2 sin(2\times 30.8)}{7.7}$

$R = 24.3 m$

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VMariaS [17]

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