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Svetach [21]
2 years ago
15

Pls help meh Kdjdjeidjndiejdididjdjjdidjdjdiejd

Physics
2 answers:
Nadya [2.5K]2 years ago
6 0

Answer:

i think b

Explanation:

i'm not sure

REY [17]2 years ago
5 0

Answer:

I think both pure substance and an element .

hope it is helpful to you ☺️☺️

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A velocity vs. time graph starts at 0 and ends at 10 m/s, stretching over a time- span of 15 s with constant acceleration. What
Alex777 [14]

Answer:

75m

Explanation:

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3 years ago
If a star contains a certain element, it can be determined by studying the star’s
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A. Emission spectrum
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3 years ago
While at the county fair, you decide to ride the Ferris wheel. Having eaten too many candy apples and elephant ears, you find th
Zepler [3.9K]

Answer:

v=3.47m/s

Explanation:

The speed is by definition the distance traveled divided over the time it takes to travel that distance. In this case, this distance is the circumference of the wheel, so we have:

v=\frac{C}{t}=\frac{2\pi r}{t}

where we have written the circumference in terms of its radius.

For our values we then obtain the value:

v=\frac{2\pi r}{t}=\frac{2\pi (16m)}{(29s)}=3.47m/s

5 0
3 years ago
Two astronauts (each with mass 100 kg) are drifting together through space. They are connected to each other by a rope 5 m in le
Nana76 [90]

Answer:

1000 kgm²/s, 400 J

1000 kgm²/s, 1000 J

600 J

Explanation:

m = Mass of astronauts = 100 kg

d = Diameter

r = Radius = \frac{d}{2}

v = Velocity of astronauts = 2 m/s

Angular momentum of the system is given by

L=mvr+mvr\\\Rightarrow L=2mvr\\\Rightarrow L=2\times 100\times 2\times 2.5\\\Rightarrow L=1000\ kgm^2/s

The angular momentum of the system is 1000 kgm²/s

Rotational energy is given by

K=I\omega^2\\\Rightarrow K=\frac{1}{2}(mr^2)\left(\frac{v}{r}\right)^2\\\Rightarrow K=mv^2\\\Rightarrow K=100\times 2^2\\\Rightarrow K=400\ J

The rotational energy of the system is 400 J

There no external toque present so the initial and final angular momentum will be equal to the initial angular momentum 1000 kgm²/s

L_i=L_f\\\Rightarrow 2mv_ir_i=2mv_fr_f\\\Rightarrow v_f=\frac{v_ir_i}{r_f}\\\Rightarrow v_f=\frac{2\times 2.5}{0.5}\\\Rightarrow v_f=10\ m/s

Energy

E_2=mv_f^2\\\Rightarrow E_2=100\times 10\\\Rightarrow E_2=1000\ J

The new energy will be 1000 J

Work done will be the change in the kinetic energy

W=E_2-E\\\Rightarrow W=1000-400\\\Rightarrow W=600\ J

The work done is 600 J

5 0
3 years ago
Explain how you can improve the accuracy of a measurement. <br>​
yKpoI14uk [10]
You use more significant figures. 5 sigfigs (1.0985) is more accurate than 2 sigfigs (1.0)
8 0
2 years ago
Read 2 more answers
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