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2 years ago

What are the 2 major organizations that develop symbols for use throughout different engineering disciplines

1 answer:

3 0

The disciplines of engineering can be divided into four main categories, chemical, civil, electrical and mechanical engineering. Each main discipline will provide you with a “taste” of the various skills and knowledge required to work in any field related to the discipline.

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Which of these are minerals? Select all that apply

adell [148]

From that particular list:

Mica (A), Quartz (B), and Copper (D) are minerals.

Steam (C) isn't.

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3 years ago

2. What are the 3<br> types of matter?

Lapatulllka [165]

Answer:

the three types of matter are solid, liquid, gas

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2 years ago

When an object loses electrons, it acquires a(n) ____________________ electric charge?

madam [21]

It acquires a positive electric charge.

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3 years ago

(d) Suppose you use a spring to launch a payload horizontally from the asteroid so that the payload ends up far from the asteroi

nydimaria [60]

Answer:

ks= 133.2 N/m

Explanation:

Assuming that we can neglect the gravitational potential energy of the mass, and that no other forces acting on the payload, total mechanical energy must be conserved.
This energy, at any time, is part elastic potential energy (stored in the spring) and part kinetic energy.
When the spring is initially compressed, the payload is at rest, so all energy is elastic potential.
Once the spring has returned to its natural state, all this elastic potential energy must have been turned into kinetic energy.
If the payload is launched horizontally, and no gravity is present,this means that its final speed will be horizontal only also, according to Newton's First Law.
So, we can write the following equation:

$\Delta U + \Delta K = 0 (1)$

where ΔU = -1/2*k*(Δx)² (2)
and ΔK = 1/2*m*v² (3)
Replacing in (2) and (3) by the givens, and simplifying, we can find the stiffness ks as follows:

$k_{s} =\frac{m*v^{2}}{\Delta x^{2}} = \frac{29 kg*(3m/s)^{2}}{(1.4m)^{2}} = 133.2 N/M (4)$

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2 years ago

A block of mass m is compressed against a spring (spring constant kk) on a horizontal frictionless surface. The block is then re

Nimfa-mama [501]

Answer:

A) True, B) False, C) False and D) false

Explanation:

Let's solve the problem using the law of conservation of energy to know if the statements are true or false

Let's look for mechanical energy

Initial

Emo = Ke = ½ k Dx2

Final

Em1= ½ m v12

Emo = Em1

½ k Δx2 = ½ m v₁²

v₁² = k / m Δx²

v₁ = √ k/m Δx

Now let's calculate the speed when it falls

Vfy² = Voy² - 2gy

Vfy² = - 2gy

Vf² = v₁² + vfy²

A) True v₁ = A Δx

.B) False. As there is no rubbing the mechanical energy conserves

.C) False the velocity is proportional to the square root of the height

v2y = v2 √2

. D) false promotional compression speed

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3 years ago