Answer:
0.06 Nm
Explanation:
mass of object, m = 3 kg
radius of gyration, k = 0.2 m
angular acceleration, α = 0.5 rad/s^2
Moment of inertia of the object
![I = mK^{2}](https://tex.z-dn.net/?f=I%20%3D%20mK%5E%7B2%7D)
I = 3 x 0.2 x 0.2 = 0.12 kg m^2
The relaton between the torque and teh moment off inertia is
τ = I α
Wheree, τ is torque and α be the angular acceleration and I be the moemnt of inertia
τ = 0.12 x 0.5 = 0.06 Nm
Gravity is an example of friction. If we didn't have gravity, we would be flying all over the place. Also, friction keeps us from sliding on the ground and falling.
Answer:
W = 320.30 J
Explanation:
To calculate the net work done over the block you take into account all implied forces:
(1)
The gravitational force and friction force are against the applied force F.
θ = 26°
F: applied force = 340N
Fg: gravitational force = Mg = (40.0kg)(9.8m/s^2) = 392N
Ff: friction force = ![\mu N=\mu Mg=(0.250)(392N)=98N](https://tex.z-dn.net/?f=%5Cmu%20N%3D%5Cmu%20Mg%3D%280.250%29%28392N%29%3D98N)
Next, you replace to obtain the net force:
![F_N=(340N)-(392N)sin(26\°)-(98N)cos(26\°)\\\\F_N=80.07N](https://tex.z-dn.net/?f=F_N%3D%28340N%29-%28392N%29sin%2826%5C%C2%B0%29-%2898N%29cos%2826%5C%C2%B0%29%5C%5C%5C%5CF_N%3D80.07N)
Finally, the net work, for 4 m, is:
![W_N=F_Nd=(80.07N)(4m)=320.30J](https://tex.z-dn.net/?f=W_N%3DF_Nd%3D%2880.07N%29%284m%29%3D320.30J)
Answer:
We cannot measure all masses in kg, because there are very small quantities like 1gm nd even smaller, and this will not be an accurate measurement in Kg.