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ASHA 777 [7]
3 years ago
11

THIS IS A SCIENCE QUESTION, sorry if it says physics, this is middle school science

Physics
1 answer:
Black_prince [1.1K]3 years ago
3 0

Answer:

1. Examples of transverse waves include vibrations on a string and ripples on the surface of water. We can make a horizontal transverse wave by moving the slinky vertically up and down. In a longitudinal wave the particles are displaced parallel to the direction the wave travels.

2. There are two basic types of wave motion for mechanical waves: longitudinal waves and transverse waves. The animations below demonstrate both types of wave and illustrate the difference between the motion of the wave and the motion of the particles in the medium through which the wave is travelling.

3. f is force and 人 is wave length

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5. A wave with peaks separated by .34 m has a wavelength of ________________m.
Eduardwww [97]

Answer: 0.17 I think

Explanation:

I asked a doctor

8 0
3 years ago
A red laser from a physics lab is marked as producing 632.8 nm light. When light from this laser falls on two closely spaced sli
goblinko [34]

Given Information:  

Wavelength of the red laser = λr = 632.8 nm

Distance between bright fringes due to red laser = yr = 5 mm

Distance between bright fringes due to laser pointer = yp = 5.14 mm

Required Information:  

Wavelength of the laser pointer = λp = ?

Answer:

Wavelength of the laser pointer = λp = ?

Explanation:

The wavelength of the monochromatic light can be found using young's double slits formula,

y = Dλ/d  

y/λ = D/d

Where

λ is the wavelength

y is the distance between bright fringes.

d is the double slit separation distance

D is the distance from the slits to the screen

For the red laser,

yr/λr = D/d

For the laser pointer,

yp/λp = D/d

Equating both equations yields,

yr/λr = yp/λp

Re-arrange for λp

λp = yp*λr/yr

λp =  (5*632.8)/5.14

λp = 615.56 nm

Therefore, the wavelength of the small laser pointer is 615.56 nm.

3 0
3 years ago
A man does 4,780 J of work in the process of pushing his 2.70 103 kg truck from rest to a speed of v, over a distance of 25.5 m.
wolverine [178]

Answer:

(A) Velocity will be 1.88 m/sec

(b) Force will be 187.45 N

Explanation:

We have given work done = 4780 j

Distance d = 25.5 m

(A) Mass of the truck m = m=2.70\times 10^3kg

We know that kinetic energy is given  by

KE=\frac{1}{2}mv^2

So v=\sqrt{\frac{2KE}{m}}=\sqrt{\frac{2\times 4780}{2.7\times 10^3}}=1.88m/sec

(B) We know that work done is given by

W = Fd

So F=\frac{W}{d}=\frac{4780}{25.5}=187.45N

4 0
3 years ago
Which statement describes the relationship between bond strength and the melting and boiling points of a substance? A. As the fo
icang [17]

Answer:

a

Explanation:

4 0
3 years ago
Why is history open to ongoing and changing interpretations?
saveliy_v [14]
History is open to ongoing and changing interpretations because changing <span>values limit interpretation. 

So your answer is A.</span>
7 0
3 years ago
Read 2 more answers
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