KE=1/2m v2= 1/2 (3kg) (2m/s)2 = 6J (6joules)
Answer:
a ) I= 1.635-i0.0021 b) ∅= -0.074
Explanation:
a) reactive impeadance= 2πfL
=2(3.14)(147)(0.158)
=145.86 Ω
Z= 171+j145.86
I=V/Z
I=278/(171+j145.86)
I= 1.635-i0.0021
b) ∅=inv.tan (-0.0021/1.635)
∅=-0.074
Explanation:
Given that,
Weight = 280 lbs
Height = 60 ft
Power = 3.50 hp
(a). We need to calculate the work done by the boom on the fireman
Using formula of work done
Put the value into the formula
The work done by the boom is 21.59 Btu.
(b). We know that,
1 hp = 550 ft lbf
So, 
We need to calculate the time
Using formula of time
Put the value into the formula
The time is 8.7 sec.
Hence, This is the required solution.
To solve for the weighted average atomic weight of X, all
we have to do is to calculate for the contribution of each isotope. The
contribution of each isotope on the atomic weight of x is calculated by
multiplying their respective atomic weights with the abundance, therefore:
X – 28 = 27.977 amu * (92.23 / 100)
X – 28 = 25.803 amu
X – 29 = 28.976 amu * (4.67 / 100)
X – 29 = 1.353 amu
X – 30 = 29.974 amu * (3.10 / 100)
X – 30 = 0.929 amu
Hence:
X = X – 28 + X – 29 + X – 30
X = 25.803 amu + 1.353 amu + 0.929 amu
<span>X = 28.085 amu</span>
It would react with metals to form hydrogen gas.
Explanation:
A compound that releases hydrogen ions in solution would most likely react with metals to form hydrogen gas.
This compound is called an acid.
- An acid is any compound that produces excess hydrogen ions in solutions.
- Most of the common acids reacts with electropositive metals to produce hydrogen gas.
learn more:
Acid brainly.com/question/11062486
#learnwithBrainly
