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seraphim [82]
3 years ago
5

Why did friction make it difficult to discover newtons first law of motion

Physics
2 answers:
Mrac [35]3 years ago
7 0

Friction made it difficult because an object in motion may not always stay in motion due to the friction caused by its movement. For instance, if you roll a ball down a straight platform, it will not go on forever. The friction of the platform and the ball with eventually slow it down and stop it.

Hope this helps!!

V125BC [204]3 years ago
6 0

Because Static Friction and Inertia can be confused, because mass defines how much inertia a body has, that is, the difficulty of putting some acceleration in it. And it's basically the same with friction. Static friction says that, for example, for you to pull a table with your hands, you need to put force (obviously), as measured by Newtons. From the Newton that the table start to accelerate, then there is the static friction.

For example:

To speed up the table, you put five Newtons, and the table does not move. Put ten, still not moving. It puts 11, and it begins to move (accelerate). So the static friction force is 10 Newtons.

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Explanation:

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What is the result of (305.120 + 267.443) x 0.50? How many answers can be written based on the principle of significant digits?
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Out of solid and liquid which has more effect on gravitation​
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What is the difference between electric field and electrostatic field?
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7 0
3 years ago
Read 2 more answers
A copper penny has a mass of 3.0 g. A total of 4.0 × 10^12 electrons are transferred from one neutral penny to another. If the e
olga55 [171]

Then the separation between the two pennies will be O.354m.

To find the correct answer, we need to know about the electrostatic force of attraction.

<h3>What is the separation between the pennies?</h3>
  • We have given with the information's,

                 m=3*10^{-3}kg\\n=4*10^{12}\\

  • As we know that the charge of one electron is 1.6×10^-19C.Thus, the total charge on the penny will be,

                 Q_1=4*10^{12}*1.6*10^{-19}=6.4*10^{-7}C.\\Q_2=-Q_1

  • We have the expression for electrostatic force of attraction as,

                    F_e=\frac{kQ_1Q_2}{r^2} =mg\\ , here given that the electrostatic force equal to the weight of the system.

  • We have to find the separation between the pennies.

                  r=\sqrt{\frac{kQ_1Q_2}{mg} } =\sqrt{\frac{(6.4*10^{-7})^2}{4*3.14*8.85*10^{-12}*3*10^{-3}*9.8} }\\\\r=0.354m

Thus, we can conclude that the separation between the pennies is 0.354m.

Learn more about the electrostatic force here:

brainly.com/question/28108740

#SPJ1

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2 years ago
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