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4 years ago

Why might people continue to pursue space exploration in the future?

1 answer:

7 0

Well people say the world's going to end soon so people need to find another planet to live on they're thinking about Mars at the moment

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What is one advantage of using a computer over a graphing calculator?

gayaneshka [121]

Among the given choices, the right statement is that computers are advantageous because it holds a larger amount of data over graphing calculators. Calculators are easier to transport and has lower power consumption. Answer here is D.

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3 years ago

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What is the pH of a 6.7 x 10^−5 M H+ solution?

lyudmila [28]

Answer:

pH = 4.17

Explanation:

According to the molar concentration you stated, pH of the solution is: 4.17

Remember that pH = - log [H⁺]

and [H⁺] = 10^-pH

When:

pH > 7 → Basic solution

pH = 7 → Neutral solution

pH < 7 → Acid solution

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3 years ago

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The freezing point of water is 0.00°C at 1 atmosphere. How many grams of nickel(II) sulfate (154.8 g/mol), must be dissolved in

VladimirAG [237]

Answer:

adsf

Explanation:

dzfgx

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3 years ago

3.2 g of a gas at STP occupies a volume of 2.24 L. The gas is

Ronch [10]

Answer:

Oxygen

Explanation:

4 0

3 years ago

Be sure to answer all parts.

MrRissso [65]

Answer: The molarity of each of the given solutions is:

(a) 1.38 M

(b) 0.94 M

(c) 1.182 M

Explanation:

Molarity is the number of moles of a substance present in liter of a solution.

And, moles is the mass of a substance divided by its molar mass.

(a) Moles of ethanol (molar mass = 46 g/mol) is as follows.

$Moles = \frac{mass}{molar mass}\\= \frac{28.5 g}{46 g/mol}\\= 0.619 mol$

Now, molarity of ethanol solution is as follows.

$Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.619 mol}{4.50 \times 10^{2} \times 10^{-3}L}\\= 1.38 M$

(b) Moles of sucrose (molar mass = 342.3 g/mol) is as follows.

$Moles = \frac{mass}{molar mass}\\= \frac{21.6 g}{342.3 g/mol}\\= 0.063 mol$

Now, molarity of sucrose solution is as follows.

$Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.063 mol}{0.067 L} (1 mL = 0.001 L)\\= 0.94 M$

(c) Moles of sodium chloride (molar mass = 58.44 g/mol) are as follows.

$Moles = \frac{mass}{molar mass}\\= \frac{6.65 g}{58.44 g/mol}\\= 0.114 mol$

Now, molarity of sodium chloride solution is as follows.

$Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.114 mol}{0.0962 L}\\= 1.182 M$

Thus, we can conclude that the molarity of each of the given solutions is:

(a) 1.38 M

(b) 0.94 M

(c) 1.182 M

4 0

3 years ago