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4 years ago

PLEASE HELP ME WITH THE CORRECT ANSWER

1 answer:

5 0

The coefficients shown in the balanced equation is showing us the reaction needs 2 moles of H2O to produce 2 moles of H2 and one mole of O2.
This means the answer is D.2

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Sound and light are both found as (4)

Mrrafil [7]

Answer:

Waves; wavelength; electromagnetic energy; ultraviolet light.

Explanation:

Sound are mechanical waves that are highly dependent on matter for their propagation and transmission.

Sound travels faster through solids than it does through either liquids or gases.

Lightwave can be defined as an electromagnetic wave that does not require a medium of propagation for it to travel through a vacuum of space where no particles exist.

Hence, sound and light are both found as waves, with a variety of wavelengths. The sun, a source of light waves specifically, releases a type of electromagnetic energy. It can be found as UVA or UVB types. These lights give off different levels of ultraviolet light, some of which can be harmful.

Additionally, the ultraviolet spectrum is divided into three categories and these are; UVA, UVB ,and UVC.

7 0

3 years ago

Calculate the volume of chlorine at stp that would be required to act completely with 3.70g of dry slaked line

myrzilka [38]

Answer:

The volume required is 2.24L

Explanation:

The slaked lime Ca(OH)2, reacts with chlorine, Cl2, as follows:

6Cl₂(g) + 3Ca(OH)₂(s) → Ca(ClO₃)₂ (aq) + 2CaCl₂ (aq) + 6HCl (aq)

Where 6 moles of chlorine react with 3 moles of slaked llime,

To solve this question we must find the moles of slaked lime added. With these moles we can find the moles of chlorine required and its volume at STP as follows:

Moles Ca(OH)2 - Molar mass: 74.093g/mol-

3.70g * (1mol / 74.093g) = 0.0500 moles Ca(OH)2

Moles Cl₂:

0.0500 moles Ca(OH)2 * (6 mol Cl₂ / 3 mol Ca(OH)2) =

0.100 moles Cl₂

Now using PV = nRT

nRT / P = V

Where n are moles: 0.100 moles

R is gas constant = 0.082atmL/molK

T is absolute temperature = 273K at STP

P is pressure = 1atm at STP

And V is volume, our incognite:

0.100mol*0.082atmL/molK*273K / 1atm = V

2.24L = Volume of Cl₂

<h3>The volume required is 2.24L</h3>

8 0

3 years ago

• Explain why each of the following pairs is not likely to form an ionic bond.

Olegator [25]

Answer:

A)Chlorine and Bromine:

They are both non metal hence they form a covalent bond due to covalent bonding.

B)Potassium and Helium:

Helium ion has a small cationic radius and distorted by the potassium ion due to polarization.

C)Sodium and Lithium:

Both are metals hence they form a metallic bond since they share electrons to the electron cloud.

4 0

3 years ago

Determine the empirical formula for compounds that have the following analyses: a. 66.0% barium and 34.0% chlorine b. 80.38% bis

almond37 [142]

Answer: a) $BaCl_2$

b) $BiO_3H_3$

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

a) Mass of Ba= 66.06 g

Mass of Cl = 34.0 g

Step 1 : convert given masses into moles.

Moles of Ba = $\frac{\text{ given mass of ba}}{\text{ molar mass of Ba}}= \frac{66.06g}{137g/mole}=0.48moles$

Moles of Cl = \frac{\text{ given mass of Cl}}{\text{ molar mass of Cl}}= \frac{34g}{35.5g/mole}=0.96moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Ba = $\frac{0.48}{0.48}=1$

For O = $\frac{0.96}{0.48}=2$

The ratio of Ba: Cl= 1:2

Hence the empirical formula is $BaCl_2$

b) Mass of Bi= 80.38 g

Mass of O= 18.46 g

Mass of H = 1.16 g

Step 1 : convert given masses into moles.

Moles of Bi = $\frac{\text{ given mass of ba}}{\text{ molar mass of Ba}}= \frac{80.38g}{209g/mole}=0.38moles$

Moles of O= $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{18.46g}{16g/mole}=1.15moles$

Moles of H= $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.16g}{1g/mole}=1.16moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Bi= $\frac{0.38}{0.38}=1$

For O = $\frac{1.15}{0.38}=3$

For H= $\frac{1.16}{0.38}=3$

The ratio of Bi: O: H= 1:3: 3

Hence the empirical formula is $BiO_3H_3$

6 0

3 years ago

Which of the following is the same as a beta particle?

IceJOKER [234]

A beta particle is the same as B. An electron. This is termed as such for a specific beta radioactive decay reaction.

8 0

3 years ago

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