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ehidna [41]
3 years ago
8

True or false: Halogens are very stable because they have a full outer shell of 8

Chemistry
1 answer:
STALIN [3.7K]3 years ago
8 0

Answer:

True

Explanation:

Halogens are very stable because they have a full outer shell of 8

true or false?

Brainiest plz and hope this answer helped let me know if you need any more help I am glad to help!

It's true!

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Which of the following best describes chicken noodle soup?
SSSSS [86.1K]
Chicken noodle soup would be considered a mixture.
3 0
3 years ago
Read 2 more answers
What if the mother is type O and the father is A? What would the offspring's blood type be?
tensa zangetsu [6.8K]

Answer:

it depends upon a his body which antigen is present

Explanation:

it depends on that person not on their parents

7 0
2 years ago
A sample of benzene was vaporized at 25◦C. When 37.5 kJ of heat was supplied, 95.0 g of the liquid benzene vaporized. What is th
grandymaker [24]

Answer:

Enthalpy of vaporization = 30.8 kj/mol

Explanation:

Given data:

Mass of benzene = 95.0 g

Heat evolved = 37.5 KJ

Enthalpy of vaporization = ?

Solution:

Molar mass of benzene = 78 g/mol

Number of moles = mass/ molar mass

Number of moles = 95 g/ 78 g/mol

Number of moles = 1.218 mol

Enthalpy of vaporization =  37.5 KJ/1.218 mol

Enthalpy of vaporization = 30.8 kj/mol

8 0
3 years ago
List two ways that the first ionization and second ionization of an atom are similar
Maru [420]
The first ionization and second ionization of an atom are similar in following ways:
1. Both ionizations involve atom and energy
2. Both lose an electron.

The difference between first and second ionization of an atom is that both started and ended with different ions/atom.
6 0
3 years ago
Find the pH of a 0.350 M aqueous benzoic acid solution. For benzoic add. Ka = 6.5 x 10^-5.
slava [35]

Answer:

correct option is (a)

The solution would be using this: C6H5COOH = H+ + C6H5COO Ka = 6.5 x 10^-5 = (H+)(C6H5COO-) over

(C6H5COOH)

Let X = moles per liter (H+) and also = moles per liter (C6H5COO-)

Ka = 6.5 x 10^-5 = (X)(X) over .350 molar = acid solution 6.5 x 10^-5 = X^2 over .350

X^2 = 6.5 x 10^-5 times .350 which = 2.275 x 10^-5

x = V2.275 x 10^-5

X = 1.5083 x 10^-5 moles per liter H+

pH = -log(H+) = -log 1.5083 x 10^-5 which

= 4.6215

7 0
3 years ago
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