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3 years ago

A horse performs 15000 joules of work pulling a wagon for 20 seconds what is the horses power

Physics

1 answer:

Illusion [34]3 years ago

8 0

To find the horse power per second. Divide 15000 by 20( 15000÷20 ). The answer is 750.

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What element shares the property of forming ions with a 1+ charge?

Oduvanchick [21]

Answer:

the Group 1A metals such as sodium and potassium form +1 charges,

Explanation:

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3 years ago

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A 2.0 x 10^3-kilogram car travels at a constant speed of 12 meters per second around a circular curve of radius 30. meters. What

Vikentia [17]

The magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²

<h3>Circular motion</h3>

From the question, we are to determine the magnitude of the centripetal acceleration.

Centripetal acceleration can be calculated by using the formula

$a_{c} =\frac{v^{2} }{r}$

Where $a_{c}$ is the centripetal acceleration

$v$ is the velocity

and $r$ is the radius

From the given information

$v = 12 \ m/s$

and $r = 30 \ m$

Therefore,

$a_{c} =\frac{12^{2} }{30}$

$a_{c} =\frac{144 }{30}$

$a_{c} = 4.8\ m/s^{2}$

Hence, the magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²

Learn more on circular motion here: brainly.com/question/20905151

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2 years ago

PLS HELP FIND THE AVREGE KENETIC ENERGY!!

ANEK [815]

Answer: if you gogle it it will tell you the awenser

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3 years ago

David is driving a steady 30.0 m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady

SpyIntel [72]

Answer:

Explanation:

Let after time t , Tina catches up David .

Distance travelled by them are equal ,

Distance travelled by Tina

s = ut + 1/2 a t²

= .5 x 2.10 t²

= 1.05 t²

Distance travelled by David

= 30 t ( because of uniform velocity )

1.05 t² = 30t

t = 28.57 s

Distance travelled by Tina

= 1/2 a t²

= .5 x 2.10 x 28.57²

= 857 m approx.

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3 years ago

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PHYSICS HELP PLEASE!! MUST SHOW MATH WORK!!

SVETLANKA909090 [29]

<u>Answer:</u>

1) Distance traveled by bird = 403 meter

2)Average speed = 1.66 km /hour

3) Zcceleration = 2 $m/s^2$

<u>Explanation:</u>

1) Distance traveled = Speed * Time taken = 31 * 13 = 403 meter.

2) Average speed = Total distance covered / Time taken for that distance to cover.

Total distance covered = 2+0.5+2.5 = 5 km

Time taken = 3 hours

Average speed = 5/3 = 1.66 km /hour

3) Acceleration is defined as the rate of change of velocity, so acceleration a = change in velocity/time.

Change in velocity = 14 - 6 = 8 m/s

Time = 4 seconds

So acceleration = 8 / 4 = 2 $m/s^2$

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3 years ago