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solmaris [256]
4 years ago
11

Suppose the initial position of an object is zero, the starting velocity is 3 m/s and the final velocity was 10 m/s. The object

moves with constant acceleration. Which part of a velocity vs. time graph can be used to calculate the displacement of the object? the area of the rectangle under the line the area of the rectangle above the line the area of the rectangle plus the area of the triangle under the line the area of the rectangle plus the area of the triangle above the line
Physics
1 answer:
Nookie1986 [14]4 years ago
8 0

Explanation:

We have,

The initial position of an object is zero.

The starting velocity is 3 m/s and the final velocity was 10 m/s.

The object moves with constant acceleration..

The area covered under the velocity-time graph gives displacement of the object. The correct option is "the area of the rectangle plus the area of the triangle under the line".

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A 125 N box is being raised from the ground floor and accelerating due to a 175 N force. Identify all the forces and find the Ne
Finger [1]

Answer:

<em>Fn = 50 N</em>

Explanation:

<u>Net Force</u>

The net force is the sum of all the forces acting on an object.

When all the forces act in a single line, the direction of the forces is given by their signs. Positive signs are assumed to be up and left on both axes.

The box being raised by a force has a weight of W=-125 N. The negative sign indicates the weight points down. The accelerating force goes up and its value is F=175 N. The positive sign indicates this force pushes the box up.

The forces acting on the box are:

The weight W=-125 N

The accelerating force F=175 N

The net force is

Fn = W + F = -125N + 175 N

Fn = 50 N

7 0
3 years ago
An engine absorbs 2150 J as heat from a hot reservoir and gives off 750 J as heat to a cold reservoir during each cycle. What is
tia_tia [17]

Answer:

65.2 %

Explanation:

Let Q1 = Heat absorbed by the system

Q2 = Heat released by the system

e= (1 - (Q2/Q1)) x 100

e= (1 - (750/2150)) x 100

e= (1 - 0.348) x 100

e= 0.652 x 100

e= 65.2 %

6 0
3 years ago
What is the energy in the spark produced by discharging the second capacitor? 1. The same as the discharge spark of the first ca
Nastasia [14]

Complete Question

The two isolated parallel plate capacitors be-  low, one with plate separation d and the other  with D > d, have the same plate area A and

are given the same charge Q.

What is the energy in the spark produced by discharging the second capacitor?

 1. The same as the discharge spark of the first capacitor

2. More energetic than the discharge spark of the first capacitor

3. Less energetic than the discharge spark of the first capacitor

Answer:

The correct option is 2

Explanation:

The formula for the energy stored in the capacitor is

             U = \frac{Q^2}{2C}

And generally the formula for finding the capacitance of a capacitor is

               C = \frac{\epsilon_oA}{d}

We can denote the capacitance of the first capacitor as C_1 = \frac{\epsilon_oA}{d}

          and   denote the capacitance of the second  capacitor as C_2 = \frac{\epsilon_oA}{D}

Looking at this formula we can see that C varies inversely with d            

as D > d it means that C_1 > C_2

                Since the charge is constant

                         U\  \alpha\ \frac{1}{C} i.e U varies inversely with C

           So C_1 > C_2   => U_2 >U_1

This means that the energy of spark would be more for capacitor two compared to capacitor one

The correct option is 2

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Answer:C

Explanation:I think sorry if it’s wrong

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A soap bubble is essentially a thin film of water surrounded by air. The colors you see in soap bubbles are produced by interfer
drek231 [11]

Answer:

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Explanation:

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6 0
3 years ago
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