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solmaris [256]
3 years ago
11

Suppose the initial position of an object is zero, the starting velocity is 3 m/s and the final velocity was 10 m/s. The object

moves with constant acceleration. Which part of a velocity vs. time graph can be used to calculate the displacement of the object? the area of the rectangle under the line the area of the rectangle above the line the area of the rectangle plus the area of the triangle under the line the area of the rectangle plus the area of the triangle above the line
Physics
1 answer:
Nookie1986 [14]3 years ago
8 0

Explanation:

We have,

The initial position of an object is zero.

The starting velocity is 3 m/s and the final velocity was 10 m/s.

The object moves with constant acceleration..

The area covered under the velocity-time graph gives displacement of the object. The correct option is "the area of the rectangle plus the area of the triangle under the line".

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What is the current in mA through a 500 Ω resistor that is connected to a 1.5 V battery? Show all calculations using Ohm’s law (
Ludmilka [50]

Answer:

3 mA.

Explanation:

The following data were obtained from the question:

Resistor (R) = 500 Ω

Potential difference (V) = 1.5 V

Current (I) =.?

Using the ohm's law equation, we can obtain the current as follow:

V = IR

1.5 = I x 500

Divide both side by 500

I = 1.5 / 500

I = 3×10¯³ A.

Therefore, the current in the circuit is 3×10¯³ A.

Finally, we shall convert 3×10¯³ A to milliampere (mA).

This can be obtained as follow:

Recall:

1 A = 1000 mA

Therefore,

3×10¯³ A = 3×10¯³ × 1000 = 3 mA

Therefore, 3×10¯³ A is equivalent to 3 mA.

Thus, the current in mA flowing through the circuit is 3 mA.

3 0
3 years ago
Which of the following is a true regarding current in an external circuit​
nata0808 [166]

The flow of an alternating current switches direction when a generator's terminals change its charge is true regarding current in an external circuit

<u>Explanation: </u>

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8 0
3 years ago
A boy pulls a sled of mass 5.0 kg with a rope that makes a 60.0° angle with respect to the horizontal surface of a frozen pond.
Oduvanchick [21]

Answer:

μk = 0.124

Explanation:

Known data

m=5.0 kg : mass of the sled

T= 10 N   : force with which the boy pulls the rope

θ =60.0°  :angle of the rope with respect to the horizontal direction

g = 9.8 m/s² : acceleration due to gravity

Newton's second law to the sled :

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass s (kg)

a : acceleration  (m/s²)

Forces acting on the sled

W: Weight of the sled : In vertical and downward direction

N : Normal force : In vertical and upwards direction

f : Friction force: parallel to the movement of the sled and in the opposite direction to the movement

T:Rope tension : forming angle 60.0° of  of the rope with respect to the horizontal direction

Calculated of the W  of the sled

W= m*g

W=  5.0 kg* 9.8 m/s² = 49 N

x-y  components  of the tension of the rope  T

Tx= 10*cos60°= 5 N

Ty=  10*sin60° = 8.66 N

Calculated of the N

We apply the formula (1)

∑Fy = m*ay    ay = 0

N+Ty -W = 0

N = 49 N  -  8.66 N

N = 40.34 N

Calculated of the f

f = μk* N

f = μk* 40.34 Equation (1)

We apply the formula (1) to calculated f

∑Fx = m*ax  the sled moves with constant velocity, then ax=0

∑Fx = 0

Tx-f = 0

5 - f = 0

f =  5N

We replace f in the equation (1)

5 = μk* 40.34

μk = 5 / 40.34

μk = 0.124

5 0
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If I spacecraft seems to be Motionless in deep space is given some type of quick push what will happen
lapo4ka [179]
It will stay in motion unless an outside force slows it down.
5 0
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Read 2 more answers
"Find the change in gravitational potential energy that the box undergoes as it rises to its final height."
Alekssandra [29.7K]

Explanation:

Given that,

Mass of a box is 2.6 kg

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Work done = Fd

= mgh

So,

W=2.6\times 9.8\times 3\\\\W=76.44\ J

(2) Now the gravitational potential energy that the box undergoes as it rises to its final height is equal to the work done by the box. So,

Change in potential energy = 76.44 J

6 0
3 years ago
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