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solmaris [256]
3 years ago
11

Suppose the initial position of an object is zero, the starting velocity is 3 m/s and the final velocity was 10 m/s. The object

moves with constant acceleration. Which part of a velocity vs. time graph can be used to calculate the displacement of the object? the area of the rectangle under the line the area of the rectangle above the line the area of the rectangle plus the area of the triangle under the line the area of the rectangle plus the area of the triangle above the line
Physics
1 answer:
Nookie1986 [14]3 years ago
8 0

Explanation:

We have,

The initial position of an object is zero.

The starting velocity is 3 m/s and the final velocity was 10 m/s.

The object moves with constant acceleration..

The area covered under the velocity-time graph gives displacement of the object. The correct option is "the area of the rectangle plus the area of the triangle under the line".

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Find the value of 02?
TiliK225 [7]
My educated guess : 21.2 deg
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3 years ago
When driving straight down the highway at a constant velocity you have to give the engine a little gas (which means an added ext
Alona [7]

Answer:

Explanation:

This does not violate Newton's 1st law because the net force would still be 0 in order to produce uniform motion (aka constant velocity). The other forces acting on the vehicles is air resistance which is non-zero. So we need car internal force to counter balance this force, which require extra gas for the car.

7 0
3 years ago
Four springs with the following spring constants, 113.0 N/m, 65.0 N/m, 102.0 N/m, and 101.0 N/m are connected in series. What is
Llana [10]

Answer:

K_e_q=22.75878093\frac{N}{m}

f=1.363684118Hz

Explanation:

In order to calculate the equivalent spring constant we need to use the next formula:

\frac{1}{K_e_q} =\frac{1}{K_1} +\frac{1}{K_2} +\frac{1}{K_3} +\frac{1}{K_4}

Replacing the data provided:

\frac{1}{K_e_q} =\frac{1}{113} +\frac{1}{65} +\frac{1}{102} +\frac{1}{101}

K_e_q=22.75878093\frac{N}{m}

Finally, to calculate the frequency of oscillation we use this:

f=\frac{1}{2(pi)} \sqrt{\frac{k}{m} }

Replacing m and k:

f=\frac{1}{2(pi)} \sqrt{\frac{22.75878093}{0.31} } =1.363684118Hz

4 0
3 years ago
How does the force the Earth exerts on you compare with the force you exert on it?
Pie

Answer:

C.Earth and you exert equal and opposite forces on each other.

Explanation:

Hello, I can help you with this

The force that the earth exerts on any object is due to the force of gravity and is known as weight, F = mg, this force is directed towards the center of the earth, in addition, according to the laws of physics for any action must have a reaction, in this case it is a force that goes out  from the ground and it is directed upwards, this force is called normal and it has the same magnitude of your weight but the opposite direction.

Have a great day.

6 0
2 years ago
A star is in hydrostatic equilibrium when the outward push of pressure due to core burning is exactly in balance with the inward
viktelen [127]

Answer:

a and b

Explanation:

Hydro static equilibrium holds a star steady and balanced. Whenever a star stops burning hydrogen in its center, there must be evolutionary improvements to maintain equilibrium for the star Of example, if a star's internal pressure and temperature fall, gravity will take over and force the star to contract and heat up, restoring stability. By contrast, if a star's internal pressure and temperature rises, the extra pressure causes the star to widen and cool, restoring balance.

so, according to above explanation options a and b both are true

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b) A small decrease in the star's internal pressure and temperature causes the star's outer layers to contract and heat up.

7 0
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