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Korvikt [17]
3 years ago
13

A sample of bismuth has a mass of 343g and volume of 35.0 cm3. what is the density of bismuth

Chemistry
1 answer:
elena-14-01-66 [18.8K]3 years ago
4 0
I don’t think I could answer this sorry.........
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HACTEHA [7]

Answer:

30 feet /second

Explanation:

60 feet/ 2 sec = 30 feet/sec

6 0
3 years ago
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A beaker is filled to the 500 mL mark with alcohol. What increase in volume (in mL) does the beaker contain when the temperature
Aliun [14]

Answer:

"1.4 mL" is the appropriate solution.

Explanation:

According to the question,

  • v_0=500
  • \alpha =1.12\times 10^{-4}
  • \Delta \epsilon = 25

Now,

Increase in volume will be:

⇒ \Delta V = \alpha\times v_0\times \Delta \epsilon

By putting the given values, we get

           =1.12\times 10^{-4}\times 500\times 25

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           =1.4  \ mL

8 0
3 years ago
Analysis of an ore of calcium shows that it contains 13.61 g calcium and 21.77 g oxygen in a 46.28-g sample. Calculate the perce
kondor19780726 [428]

Answer:

29.41% of Calcium and 47.04% of Oxygen

Explanation:

The percent composition of an atom in a molecule is defined as 100 times the ratio between the mass of the atom and the mass of the molecule.

The mass of the molecule of the problem (Ore) is 46.28g. That means the percent composition of Calcium is:

13.61g / 46.28g * 100 = 29.41% of Calcium

And percent composition of Oxygen is:

21.77g / 46.28g * 100 = 47.04% of Oxygen

5 0
3 years ago
Suggest a way of improving
bezimeni [28]

Explanation:

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4 0
3 years ago
Determine the molarity of a solution formed by dissolving 97.7 g libr in enough water to yield 750.0 ml of solution.
rewona [7]

Answer:

1.5 M.

Explanation:

  • Molarity (M) is defined as the no. of moles of solute dissolved in a 1.0 L of the solution.

<em>M = (no. of moles of LiBr)/(Volume of the solution (L).</em>

<em></em>

∵ no. of moles of LiBr = (mass/molar mass) of LiBr = (97.7 g)/(86.845 g/mol) = 1.125 mol.

Volume of the solution = 750.0 mL = 0.75 L.

∴ M = (no. of moles of luminol)/(Volume of the solution (L) = (1.125 mol)/(0.75 L) = 1.5 M.

3 0
4 years ago
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