A sample of bismuth has a mass of 343g and volume of 35.0 cm3. what is the density of bismuth

What does it mean to be recyclable? What are a few recyclable materials?

Bond [772]

Rigid Plastics/Bottles. - Any plastic bottles or containers found in your kitchen.
Paper and Cardboard. - Cereal/snack cardboard boxes. ...
Metals. - Tin, aluminum, and steel cans.
Glass. - Food containers or jars. ...
Loose Plastic Bags. - Plastic shopping bags. ...
Polystyrene Foam Cups or Containers. ...
Soiled Food Items. ...
Other.
DescriptionRecycling is the process of converting waste materials into new materials and objects. It is an alternative to "conventional" waste disposal that can save material and help lower greenhouse gas emissions.
Sorry if this is incorrect :(

6 0

3 years ago

Read 2 more answers

Which of the following has a central atom that exceeds the octet rule? PCl5 BeF2 H2S CO2

kherson [118]

Schwarzschild Radius here.

So,

The octet rule really only holds up for the second period elements, and only certain elements in that period, for that matter. Elements in the third periods and beyond can have expanded octets.

Draw Lewis dot diagrams for each molecule.

$PCl_5$ :

P is the central atom bonded individually to each Cl. The only logical diagram is that with three lone pairs surrounding each Cl and the P single-bonded to each Cl atom. If you count the bonds, you will find that P has five pairs, or 10 electrons. This exceeds the octet rule.

$BeF_2$ :

The Lewis dot diagram for this molecule is a linear molecule with the Be in the center, singly bonded to both F's, each of which have three lone pairs. This means Be has only two pairs, or four electrons. While not an example of a central atom that exceeds the octet rule, Be is one of the special elements that can stably have an incomplete octet.

$H_{2}S$ :

The most stable diagram for this molecule is with S in the center with two lone pairs and singly bonded to each H atom. With four pairs, or 8 electrons, this molecule obeys the octet rule.

$CO_2$ :

The diagram for this molecule is C in the center doubly bonded to each O atom. Each O atom has 2 lone pairs. C has four pairs, or 8 electrons. This molecule also obeys the octet rule.

Hope this helps!

7 0

3 years ago

Neptunium's only naturally occurring isotope, 23793np, decays by emitting one alpha particle, one beta particle, and one gamma r

Olin [163]

The given isotope of Neptunium is $^{237} _{93} Np$

Alpha decay of an isotope results in daughter nuclide with mass number less by 4 units and atomic number less by 2 units than the parent isotope.

Alpha decay of Neptunium-237 can be represented as:

$^{237} _{93} Np-->^{233}_{91} Pa+^{4} _{2} He$

Beta decay of the above formed protactinium nuclide can be represented as:

$^{233}_{91}Pa-->^{233} _{92} U+^{0}_{-1}e$

Gamma decay releases only energy in the form of gamma rays, the nuclide remains the same.

$^{233}_{92}U-->^{233}_{92}U+$ γ

The new atom formed after the given decays is $^{233}_{92}U$

5 0

3 years ago

A rigid, closed vessel of volume V =648 liters maintained at constant temperature T=365 K is loaded with 112 mol of n-hexane, 15

Marrrta [24]

Answer:

P = 2.92 atm

Explanation:

With the three assumptions in mind, the system consists of:

A liquid phase containing n-hexane and n-heptane, and

A gaseous phase containing n-hexane vapor, n-heptane vapor, and nitrogen gas.

First we use PV=nRT to calculate the moles of n-hexane and n-heptane in the gaseous phase:

n-hexane:

P = 0.199 MPa ⇒ 0.199 * 1.869 = 1.964 atm

1.964 atm * 648 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 365 K

n = 42.52 moles

n-heptane:

P = 0.083 MPa ⇒ 0.083 * 1.869 = 0.155 atm

0.155 atm * 648 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 365 K

n = 3.358 moles

So the gaseous phase consists of 42.52 moles of n-hexane, 3.358 moles of n-heptane, and 14 mol of nitrogen.

For the liquid phase, we calculate the remaining moles of n-hexane and n-heptane. Then we convert to liters, using their molar volumes:

n-hexane:

n = 112 mol - 42.52 mol = 69.48 mol

69.48 mol * 0.146 L/mol = 10.14 L

n-heptane:

n = 155 mol - 3.358 mol = 151.642 mol

151.642 mol * 0.162 L/mol = 24.57 L

So the liquid phase occupies (10.14+24.57) = 34.71 L, and contains 69.48 mol of n-hexane and 151.64 mol of n-heptane.

Finally, to calculate the pressure in the vessel, we use PV=nRT:

P = ?

V = 648 - 34.71 = 613.29 L

n = 42.52 mol hexane + 3.35 mol heptane + 14 mol nitrogen = 59.87 mol

T = 365 K

P * 613.29 L = 59.87 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 365 K

P = 2.92 atm

6 0

3 years ago

The observed rotation of 2.0 gg of a compound in 50 mLmL of solution in a polarimeter tube 25-cmcm long is +47.2 ∘∘ . What is th

Anastaziya [24]

Answer:

[∝] = +472

Explanation:

Specific rotation in a solution is defined as:

[∝] = ∝ / c×l

Where:

[∝] is specific rotation, ∝ is observed rotation (In degrees), c is concentration in g/mL and l is path length (In dm).

∝: +47.2°

c: 2.0g / 50mL = 0.04g/mL

l: 25cm × (1dm /10cm) = 2.5dm

Replacing:

[∝] = +47.2° / 0.04g/mL×2.5dm = +472

I hope it helps!

4 0

3 years ago