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Readme [11.4K]
3 years ago
10

For an atom’s electrons, how many energy sublevels are present in the principal energy level n = 4? 4 9 10 16 32

Chemistry
2 answers:
Ghella [55]3 years ago
8 0
I believe the answer is 32.
Hope that helps.
Kipish [7]3 years ago
3 0

<u>Answer:</u> The number of sub-levels the for the energy level n = 4 are 4.

<u>Explanation:</u>

The number of sub-levels in an energy level is determined from the azimuthal quantum number.

<u>Principle Quantum Number:</u> This quantum number describes the size of the orbital. It is represented by n where n = 1,2,3,4....

<u>Azimuthal Quantum Number:</u> This quantum number describes the shape of the orbital and also determines the sub-levels in an energy level. It is represented by the symbol 'l'. The value of 'l' ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

For n = 4, the value of l = 0(s), 1(p), 2(d), 3(f) and these are the number of sub-levels.

Hence, the number of sublevels the for the energy level n = 4 are 4.

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The structure of the alkyl bromides used in a malonic ester synthesis of ethyl 2-methyl-4-pentenoate.

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Answer:

Option 1. NO

Explanation:

The balanced equation for the reaction is given below below:

4NH₃ + 6NO —> 5N₂ + 6H₂O

From the balanced equation above,

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Finally, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

4 moles of NH₃ reacted with 6 moles of NO.

Therefore, 1.24 moles of NH₃ will react with = (1.24 × 6)/4 = 1.86 moles of NO

From the calculation made above, we can see that a higher amount of NO (i.e 1.86 moles) than what was given (i.e 1.79 moles) is needed to react completely with 1.24 moles of NH₃.

Therefore, NO is the limiting reactant and NH₃ is the excess reactant.

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The 0.05 moles of Na_{3}PO_{4} required to make 1 L of solution in which the Na concentration is 0. 15 M.

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To make 1. L of solution in which the  Na^{+concentration is 0. 15 M

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number of moles of Na^{+ = 0.15 mole

The mole ratio is 1: 3

It means, the 1 mole of Na_{3}PO_{4}(s) required to form 3 mole of Na^{+

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