1 mole C₆H₁₂O₆ ------------- 6 moles oxygen
3 moles <span>C₆H₁₂O₆ ----------- X
X = (3</span>×6)/1
<u>X = 18 moles</u>
:)
Answer:
1.008moles of iodine
Explanation:
Hello,
This question requires us to calculate the theoretical yield of I₂ or number of moles that reacted.
Percent yield = (actual yield / estimated yield) × 100
Actual yield = 1.2moles
Estimated yield = ?
Percentage yield = 84%
84 / 100 = 1.2 / x
Cross multiply and solve for x
100x = 84 × 1.2
100x = 100.8
x = 100.8/100
x = 1.008moles
1.008 moles of I₂ reacted in excess of H₂ to give 1.2 moles of HI
The answer is C. Hydrogen Bond
Answer:
The partial pressure of ammonia at equilibrium when a sufficient quantity of ammonium iodide is heated to 400°C Is 0.103 atm.
The correct option is A.
Explanation;
NH4I(s) ⇋ NH3(g) + HI(g)Kp = 0.215 at 400°C
NH4I(s)= 0.215
NH3(g)=0.103
HI(g)Kp=0.112
Therefore = 0.103 +0.112= 0.215
Therefore the partial pressure of ammonia at equilibrium is 0.103 atm
