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Ipatiy [6.2K]
3 years ago
6

This whole worksheet. I am not good at this and I am completely lost

Physics
1 answer:
Ket [755]3 years ago
3 0
1.) potential energy
2.)potential and kinetic
3.)The roller coaster car has the most kinetic energy at point X i know this because the car is moving and kinetic energy has the power to move or change things therefore point X is when the roller coaster car has the most energy.
4.)potential energy
5.)kinetic energy
6.) potential and kinetic energy
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Physical change
Because it's changed by heat
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Which of the following provides the best evidence in support of the big bang
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C. The Uniformity of Cosmic Background Radiation

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A 1200 kg cannon fires a 100.0 kg cannonball at 52 m/s. What is the recoil velocity of the cannon? Assume that frictional forces
alina1380 [7]

Answer:

A) 4.3 m/s

Explanation:

M = mass of the cannon = 1200 kg

m = mass of the cannonball = 100 kg

v = speed of the cannonball after the fire = 52 m/s

V = speed of cannon after fire

Since the cannon and cannonball were at rest before fire, total initial momentum will be taken as 0

Using conservation of momentum

0 = m v - M V

M V = m v

inserting the values

(1200) V = (100) (52)

V = 4.3 m/s

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3 years ago
Discuss what it means to view a moving objectt from a frame of reference. Supply an example that illustrates your explanation.
tekilochka [14]
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3 years ago
. A long 10-cm-diameter steam pipe whose external surface temperature is 110oC passes through some open area that is not protect
Nata [24]

Answer:

Nu = 30.311

Explanation:

Let consider that pipe is a horizontal cylinder. The Nusselt number is equal to:

Nu = \left\{0.6+\frac{0.387\cdot Ra_{D}^{\frac{1}{6} }}{[1+\left(\frac{0.559}{Pr}  \right)^{\frac{9}{16}} ]^{\frac{8}{27} }}  \right\}^{2}, for Ra_{D} \le 10^{12}.

Where Ra_{D} is the Rayleigh number associated with the cylinder.

The Rayleigh number is:

Ra_{D} = \frac{g\cdot \beta\cdot (T_{pipe}-T_{air})\cdot D^{3}}{\nu^{2}}\cdot Pr

By assuming that air behaves ideally, the coefficient of volume expansion is:

\beta = \frac{1}{T}

\beta = \frac{1}{283.15\,K}

\beta = 3.532\times 10^{-3}\,\frac{1}{K}

The cinematic and dynamic viscosities, thermal conductivity and isobaric specific heat of air at 10 °C and 1 atm are:

\nu = 1.426\times 10^{-5}\,\frac{m^{2}}{s}

\mu = 1.778\times 10^{-5}\,\frac{kg}{m\cdot s}

k = 0.02439\,\frac{W}{m\cdot ^{\textdegree}C}

c_{p} = 1006\,\frac{J}{kg\cdot ^{\textdegree}C}

The Prandtl number is:

Pr = \frac{\mu\cdot c_{p}}{k}

Pr = \frac{(1.778\times 10^{-5}\,\frac{kg}{m\cdot s} )\cdot (1006\,\frac{J}{kg\cdot ^{\textdegree}C} )}{0.02439\,\frac{W}{m\cdot ^{\textdegree}C} }

Pr = 0.733

Likewise, the Rayleigh number is:

Ra_{D} = \frac{(9.807\,\frac{m}{s^{2}} )\cdot (3.532\times 10^{-3}\,\frac{1}{K} )\cdot (110^{\textdegree}C-10^{\textdegree}C)\cdot (0.1\,m)^{3}}{(1.426\times 10^{-5}\,\frac{m^{2}}{s})^{2} }\cdot (0.733)

Ra_{D} = 12.486\times 10^{6}

Finally, the Nusselt number is:

Nu = \left\{0.6+\frac{0.387\cdot (12.486\times 10^{6})^{\frac{1}{6} }}{\left[1 + \left(\frac{0.559}{0.733}\right)^{\frac{9}{16} }\right]^{\frac{8}{27} }}  \right\}^{2}

Nu = 30.311

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3 years ago
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