Hey there,
So. . I believe is how you do it. I did 350 x 3.0 and it got me 1,050.
We always multiply it by when it come to the initial volume of the gas.
Hope this helps.
~Jurgen<span />
Answer is: 25,06 kJ of energy must be added to a 75 g block of ice.
ΔHfusion(H₂O) = 6,01 kJ/mol.
T(H₂O) = 0°C.
m(H₂O) = 75 g.
n(H₂O) = m(H₂O) ÷ M(H₂O).
n(H₂O) = 75 g ÷ 18 g/mol.
n(H₂O) = 4,17 mol.
Q = ΔHfusion(H₂O) · n(H₂O)
Q = 6,01 kJ/mol · 4,17 mol
Q = 25,06 kJ.
Answer: 5moles
Explanation:
1mole of a substance contains 6.02x10^23 molecules.
Then, 1mole of CO also contains 6.02x10^23 molecules.
If 1 mole of CO2 contains 6.02x10^23 molecules, it means Xmol of CO contains 3.01 E24 ie 3.01x10^24 molecules
Xmol of CO = 3.01x10^24 / 6.02x10^23
Xmol = 5moles
the oxidation state of each atom
Complete Question
The complete question is shown on the first uploaded image
Answer:
Answer: 760 uM
Explanation:
the addition of solvent to a solution in a such away that the volume of the solution increases and the concentration decreases is a process know as dilution
The concentration and the volume of the dilute and concentrated solution are given below as follows
Concentrated solution Dilute solution
Given that M1 = 97.0uM
V1 = 47.0 mL
V2 = 6.0 mL
M2 = ?
Therefore M1V1 = M2V2
M2 = M1V1/V2
M2 = (97*47)/6
M2 = 760 uM
Answer: 760 uM
