Question

Which of the following is a possible Noble gas notation? [Xe] 6s26p6 [Kr] 5s25d85p6 [Xe] 6s25d106p4 [Kr] 5s24d105p6

Answer 1

Answer is: [Kr] 5s24d105p6.

1) [Xe] 6s²6p⁶ is not correct, because element with atomic number 62 (54 + 8) is samarium with electron configuration [Xe] 6s²4f⁶.

Xenon (Xe) is noble gas with atomic number 54, which means it has 54 protons and 54 electrons.

Electron configuration of xenon atom:  

₅₄Xe 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶.

2) [Kr] 5s²5d⁸5p⁶ is not correct, because element with atomic number 52 (36 + 16) is tellurium.

Tellurium (Te) is an element with atomic number 52 (52 protons and 52 electrons), it is in group 16 (chalcogens) and period 5 (principal quantum number n = 5, which means it has 5 electrons shell) of Periodic table.

Electron configuration of tellurium atom:

₅₂Te 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁴ or [Kr] 4d¹⁰5s²5p⁶.

Krypton is a chemical element with symbol Kr and atomic number 36, which means it has 36 protons and 36 electrons.

Electron configuration of krypton atom:  

₃₆Kr 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶.

3) [Xe] 6s²5d¹⁰6p⁴ is not correct, because element with atomic number 70 (54 + 16) is ytterbium (Yb) with electron configuration [Xe] 6s²4f¹⁴.

4) [Kr] 5s²4d¹⁰5p⁶ is correct, because element with atomic number 54 (36 + 18) is krypton (Kr) with electron configuration 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ or [Kr] 5s²4d¹⁰5p⁶.

Answer 2

D. [Kr] 5s24d105p6

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