Answer:
Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Ca^2 , Al^3 ,I^-,S^2-
Explanation:
1)Formula of calcium iodide:
The compound of Ca^2+ and I^-1:
2) Formula of calcium sulfide:
3) Formula of aluminum iodide:
4) Formul aluminum sulfide:
These are the four ionic compounds that are formed.
Answer:
Molecular formula = C₄F₈
Explanation:
Given data:
Empirical formula of compound = CF₂
Molar mass of compound = 200.4 g/mol
Molecular formula of compound = ?
Solution:
Formula:
Molecular formula = n ( empirical formula)
n = Molar mass of compound / empirical formula mass
empirical formula mass = CF₂ = 12+19×2 = 50 g/mol
n = 200.4 g/mol / 50 g/mol
n = 4
Molecular formula = n ( empirical formula)
Molecular formula = 4 ( CF₂)
Molecular formula = C₄F₈
Answer:
it's-D...........................
Answer:
- 6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂
Explanation:
<em>Photosynthesis</em> is the chemical process carried out by plants for the conversion of inorganic matter (carbon dioxide and water) into organic matter (glucose) with the release of oxygen, using light (sun energy).
So the chemical process may be represented by:
carbon dioxide + water + sun energy → glucose + oxygen
- <u>Skeleton equation:</u>
CO₂ + H₂O + sun energy → C₆H₁₂O₆ + O₂
- <u>Balanced chemical equation:</u>
6CO₂ + 6H₂O + sun energy → C₆H₁₂O₆ + 6O₂
- <u>Supressing the energy to show only the chemical compounds:</u>
6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂
Answer:
C. 0.4.
Explanation:
<em>∵ mole fraction of acetic acid (X acetic acid) = (no. of moles acetic acid)/(total no. of moles) = (no. of moles acetic acid)/(no. of moles of acetic acid + no. of moles of water).</em>
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- no. of moles of acetic acid = 2, no. of moles of water = 3.
- Total no. of moles = no. of moles of acetic acid + no. of moles of water = 2 + 3 = 5.
<em>∴ mole fraction of acetic acid (X acetic acid) = (no. of moles acetic acid)/(total no. of moles) =</em> (2)/(5)<em> = 0.4.</em>
