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Radda [10]
3 years ago
5

A cylindrical object has a diameter of 1.25 cm and a height of 6.48 cm. what is its volume?

Chemistry
1 answer:
Svetradugi [14.3K]3 years ago
7 0

The volume of cylinder = 7.948 cm³

Further explanation

Volume is a derivative quantity derived from the length of the principal

The unit of volume can be expressed in liters or milliliters or cubic meters

The volume of the aquarium is almost the same as the beam namely:

V = length x width x height

The volume of a cylinder can be formulated :

\tt V=\pi.r^2.h

r = radius

h = height

  • radius

Diameter of cylinder = 1.25 cm

radius=r :

\tt \dfrac{1.25}{2}=0.625~cm

  • volume

\tt V=\pi\times 0.625^2\times 6.48\\\\V=\boxed{\bold{7.948~cm^3}}

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Answer:

Which sequence of events is required to form a limestone cave where you can walk around and observe cave formations, such as stalactites? (Note: stalactites hang from the ceiling - they have to hold on tight to the roof.)

A geological sequence of events as involving the lowering of the water table to expose cave structures where stalactites and stalagmites form which is described as follows,

Explanation:

1. Acidic percolated water formed cavities of solution beneath the natural water table known as phreatic zone

2. After the passage of time there is a drop in the water table dropped forming caves from cavities

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Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 5.90 moles of magnesium perchlorate, Mg(ClO4)2.
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5.90, 11.8, 47.2

Explanation:

Let’s remove the parentheses and write the formula as MgCl₂O₈.

We see that 1 mol Mg(ClO₄)₂ contains 1 mol Mg atoms, 2 mol Cl atoms, and 8 mol O atoms.

∴ \text{Moles of Mg atoms} = \text{5.90 mol Mg(ClO}_{4})_{2} \times \frac{\text{1 mol Mg atoms}} {\text{1 mol Mg(ClO}_{4})_{2}} = \text{5.90 mol Mg atoms}  

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Answer:

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