All categories

3 years ago

Help!: Determine the mass of oxygen that can be removed from 25.0 grams of Fe2O3?

Chemistry

1 answer:

Lorico [155]3 years ago

3 0

7.5g

Explanation:

Given parameters:

Mass of Fe₂O₃ = 25g

Unknown:

Mass of oxygen that can be removed = ?

Solution:

Find the ratio of the oxygen atoms to that of the compound using the molar mass. Then multiply with the given mass.

Mass of oxygen = $\frac{molar mass of oxgygen}{molar mass of [tex]Fe_{2}O_{3}$ }[/tex] x given mass

Mass of oxygen = $\frac{3 x 16}{160}$ x 25 = 7.5g

Learn more:

Percentage composition brainly.com/question/8654167

#learnwithBrainly

You might be interested in

How does the energy of an electorn change when the electron moves closer to the nucleus?

stellarik [79]

Answer:

when an electron move closer to the nucleus the magnitude of energy of the nucleus increases

8 0

2 years ago

In an experiment, 34.8243g of copper (II) nitrate hydrate, Cu(NO3)2•zH2O was heated to a constant mass of 27.0351g. Calculate th

Leto [7]

Answer:

1) The mass of water lost = 7.7892 grams

2) Z = 3: Cu(NO3)2*3H2O

Explanation:

Step 1: Data given

Mass of copper (II) nitrate hydrate, Cu(NO3)2•zH2O = 34.8243 grams

Mass of substance after heating = 27.0351 grams

Molar mass of Cu(NO3)2 = 187.56 g/mol

Molar mass of H2O = 18.02 g/mol

Step 2: Calculate mass of water

The mass of water is the mass lost after heating.

Mass water = 34.8243 - 27.0351 = 7.7892 grams of water

Step 3: Calculate moles of Cu(NO3)2

Moles Cu(NO3)2 = Mass Cu(NO3)2 / Molar mass Cu(NO3)2

Moles Cu(NO3)2 = 27.0351 grams / 187.56 g/mol

Moles Cu(NO3)2 = 0.144 moles

Step 4: Calculate moles of H2O

Moles H2O = 7.7892 grams / 18.02 g/mol

Moles H2O = 0.432 moles

Step 5: Calculate Z

z = moles H2O / moles Cu(NO3)2

Z = 0.432/0.144

Z = 3

This means we have 3 water molecules in the formula. This makes the formula ofthe hydrate: Cu(NO3)2*3H2O

5 0

3 years ago

Consider the resonance structures for the carbonate ion. carbonate is a carbon double bonded to an oxygen with two lone pairs an

Bumek [7]

Answer:

The correct answers are: Each oxygen of carbonate ion has -2/3 or -0.67 charge.

Bond order of each carbon‑oxygen bond in the carbonate ion = 1.33

Explanation:

The carbonate ion (CO₃²⁻) is an organic compound, in which a carbon atom is covalently bonded to three oxygen atoms. The net formal charge on a carbonate ion is −2.

The carbonate ion is resonance stabilized and has three equivalent resonating structures, which exhibits that all the three carbon-oxygen bonds in a carbonate ion are equivalent.

In the resonance hybrid of carbonate ion, the negative charge is equally delocalized on all the three oxygen atoms.

Thus, each bonded oxygen has -2/3 or -0.67 charge.

In a carbonate ion there is one double bond oxygen (C=O) and two single bonded oxygen (C-O). Bond order of 1 C=O is 2 and bond order of C-O is 1.

∴ Bond order = sum of all bond orders ÷ number of bonding groups = (2+1+1) ÷ 3 = 1.33

8 0

3 years ago

Predict the products of the double replacement reactions given. Check to see that the equations are

Angelina_Jolie [31]

Answer:

Option (2)

Explanation:

The two compounds formed will be AgCl and NaNO₃.

We can see that this will result in a balanced equation, so the answer is Option (2).

4 0

2 years ago

Able 1 Cell Type Operating Cell Potential for Commercial Batteries, E (V) Lithium-iodine Zinc-mercury +2.80 +1.35 Table 2 Standa

IrinaK [193]

Answer:

During the initial cell operation, each reaction is thermodynamically favorable, but the larger operating potential of the lithium-iodine cell indicates that its cell reaction is more thermodynamically favorable. ( B )

During the initial cell operation, the oxidation of iodine is thermodynamically favorable but the oxidation of mercury is not. ( C )

Explanation:

The major Differences between The Zinc mercury cell and Lithium-iodine cell are :

During the initial cell operation, the oxidation of iodine is thermodynamically favorable but the oxidation of mercury is not.

Given the relationship below,

Δ G = -nFE

E = emf of cell , G = free energy.

This relationship shows that if E is positive the reaction will be thermodynamically favorable also if E is large it will increase the negativity of free energy also From the question we can see that with the reduction of mercury the value of E is more positive and this shows that Mercury is thermodynamically unfavorable

8 0

2 years ago