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3 years ago

Draw velocity-ime graph for uniform moion of an object , when initially body is at rest.

1 answer:

Klio2033 [76]3 years ago

8 0

When the body is at rest, its speed is zero, and the graph lies on the x-axis.

When the body is in uniform motion, the speed is constant, and the graph is a horizontal line, parallel to the x-axis and some distance above it.

It's impossible to tell, based on the given information, how these two parts of the
graph are connected. There must be some sloping (accelerated) portion of the graph
that joins the two sections, but it cannot be accounted for in either the statement
that the body is at rest or that it is in uniform motion, since acceleration ... that is,
any change of speed or direction ... is not 'uniform' motion'.

You might be interested in

Calculate the speed of a body covering a distance of 320 km in 4h

Mice21 [21]

We have that the speed of a body covering a distance of 320 km in 4h is mathematically given as

V=22.22m/s is

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Speed</h3>

From the question we are told

calculate the speed of a body covering a distance of 320 km in 4h

Generally the equation for the Speed is mathematically given as

$V=\frac{distance }{time}\\\\Therefore\\\\V=\frac{320*1000}{4*60*60}\\\\$

V=22.22m/s

Hence

The speed of a body covering a distance of 320 km in 4h is

V=22.22m/s

For more information on Speed visit

brainly.com/question/7359669

4 0

2 years ago

What are two ways air resistance can be increased?

elena-14-01-66 [18.8K]

The increase in speed leads to an increase in the amount of air resistance. Eventually, the force of air resistance becomes large enough to balances the force of gravity. At this instant in time, the net force is 0 Newton; the object will stop accelerating. The object is said to have reached a terminal velocity.

7 0

3 years ago

A skier leaves the horizontal end of a ramp with a velocity of 25.0 m/s and lands 70.0 m from the base of the ramp. How high is

Valentin [98]

Answer:

The end of the ramp is 38.416 m high

Explanation:

Horizontal Motion

When an object is thrown horizontally with an initial speed v and from a height h, it follows a curved path ruled by gravity.

The maximum horizontal distance traveled by the object can be calculated as follows:

$\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}$

If the maximum horizontal distance is known, we can solve the above equation for h:

$\displaystyle h=\frac {d^2g}{2v^2}$

The skier initiates the horizontal motion at v=25 m/s and lands at a distance d=70 m from the base of the ramp. The height is now calculated:

$\displaystyle h=\frac {70^2\cdot 9.8}{2\cdot 25^2}$

$\displaystyle h=\frac {4900\cdot 9.8}{2\cdot 625}$

h= 38.416 m

The end of the ramp is 38.416 m high

8 0

2 years ago

If the action force is the swimmer pushing water in the leftward direction, what is the reaction force?

Sphinxa [80]

According to Newton's Third Law of Motion, to every action, there is an equal and opposite reaction; action and reaction act on different bodies.
Here, the action force is in the leftward direction, so the reaction will be in the opposite direction.
If the action force is the swimmer pushing water in the leftward direction, then the reaction force is in the rightward direction.
And the reaction force will be given by the water on the swimmer.

Answer:

The reaction force is the water pushing the swimmer in the rightward direction.

Hope you could get an idea from here.

Doubt clarification - use comment section.

3 0

2 years ago

An object accelerates from rest and travels 53 m west in 5.2 s. Determine the acceleration

zmey [24]

Answer:

20.4m/s²

Explanation:

Given parameters:

Initial velocity = 0m/s

Distance = 53m

Time = 5.2s

Unknown:

Acceleration = ?

Solution:

This is a linear motion and we use the right motion equation;

S = ut + $\frac{1}{2}$ at²

S is the distance

u is the initial velocity

a is the acceleration

t is the time

Insert the parameters and solve;

53 = (0x 5.2) + $\frac{1}{2}$ x a x 5.2

53 = 2.6a

a = $\frac{53}{2.6}$ = 20.4m/s²

6 0

3 years ago