The Richter Scale<span> is not commonly </span>used<span> anymore, except for small </span>earthquakes<span>recorded locally, for which ML and Mblg are the only </span>magnitudes<span> that can be measured. For all other </span>earthquakes<span>, the </span>moment magnitude scale<span> is a more accurate measure of the </span>earthquake<span> size.</span>
The free fall of the phone is an uniformly accelerated motion toward the ground, with constant acceleration equal to

So, assuming the downward direction as positive direction of the motion, since the phone starts from rest the distance covered by the phone after a time t is given by

And if we substitute t=2.7 s, we find the distance covered:
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Answer:
The angular speed of the sphere at the bottom of the hill is 31.39 rad/s.
Explanation:
It is given that,
Weight of the sphere, W = 240 N
Radius of the sphere, r = 0.2 m
Angle with the horizontal, 
We need to find the angular speed of the sphere at the bottom of the hill if it starts from rest.
As per the law of conservation of energy, the total energy at the top is equal to the energy at the bottom.
Gravitational energy = translational energy + rotational energy
So,

I is the moment of inertia of the sphere, 
Also, 
h is the height of the ramp, 

On solving the above equation we get :



So, the angular speed of the sphere at the bottom of the hill is 31.39 rad/s. Hence, this is the required solution.