When the cannonball is fired from the cliff, it will most closely follow the path 2.
<h3>What is a projectile motion?</h3>
This a type of motion in which the projectile experiences the influence of Earth gravity causing the projectile take a parabolic or curved trajectory.
The cannonball is an example of a projectile and its path of motion will be parabolic or curved.
From the given graph;
- The path 1 is a linear path
- The path is a parabolic path
- The path 3-5 is linear and curved
Thus, when the cannonball is fired from the cliff, it will most closely follow the path 2.
Learn more about trajectory of a projectile here: brainly.com/question/1912408
Initially, mg = kx. K = mg/x = 700/0.5x10^-3 = 1400000N/m. From second condition, applying work-energy theorem, potential enery- elastic potential energy = change in kinetic energy. Now change in kinetic energy is 0 since initial and final velocities are 0m/s. Therefore, potential energy = elastic potential energy. mgh = (1/2) * k* x^2. x^2 = 2(mg)h/k = 2 x 700 x 1.3/ 1400000. x = 0.036m. Hope it's clear.
Explanation:
The object is moving along the parabola y = x² and is at the point (√2, 2). Because the object is changing directions, it has a centripetal acceleration towards the center of the circle of curvature.
First, we need to find the radius of curvature. This is given by the equation:
R = [1 + (y')²]^(³/₂) / |y"|
y' = 2x and y" = 2:
R = [1 + (2x)²]^(³/₂) / |2|
R = (1 + 4x²)^(³/₂) / 2
At x = √2:
R = (1 + 4(√2)²)^(³/₂) / 2
R = (9)^(³/₂) / 2
R = 27 / 2
R = 13.5
So the centripetal force is:
F = m v² / r
F = m (5)² / 13.5
F = 1.85 m
Answer:
a = 2 m/s^2
which agrees with the third answer option provided.
Explanation:
Recall the kinematic formula for displacement under the action of a constant acceleration "a":
yf - yi = 1/2 a t^2
using the information provided this equation becomes:
9 = 1/2 a (3)^2
solve for a:
9 * 2 / 9 = a
then a = 2 m/s^2
which agrees with the third answer option provided.