Answer:
the solid particles that settle down at the bottom of the container are known as sediment.
Explanation:
Answer:
I am sure the awnser to this is
B. vibrate
Answer:
4 Km/hr
Explanation:
Data obtained from the question include the following:
Mass of ball (Mb) = 15 Kg
Velocity of ball (Vb) = 20 Km/hr
Mass skater (Ms) = 60 Kg
Velocity of skater (Vs) = 0 Km/hr
Velocity after collision (V) =..?
Thus, we can obtain the velocity after collision as follow:
MbVb + MsVs = V(Mb + Ms)
(15 x 20) + (60 x 0) = V (15 + 60)
300 + 0 = 75V
300 = 75V
Divide both side by 75
V = 300/75
V = 4 Km/hr.
Therefore, the velocity after the collision is 4 Km/hr.
Answer:
C or A
Explanation:
please do part B!
Part 2: Problems Problem 1:12 points An Atwood machine is made of two masses m! = 0 15 kg and m2 = 0 1 kg attached to lightweight (i.e. massless) string placed over a pulley. As always the string does not stretch. The pulley is made of a disk of mass M-0.5 kg and radius R = 0.1 m. The two masses are initially at rest at the same height yinitial-0.75 m above the ground. Use 10 m/s2 for this problem A. Calculate the acceleration of the two masses once they are free to move a. 0.25 m/s b. 0.5 m/s2 d. 2.0 m/s2 B. One second after the motion begins what are the heights yi and y2 of the two masses above the gro a. yi-0.25 m and Y2 1.25 m . 21.5nm c. y,-1.0 m and Y2 = 0.5 m d. = 1.5 m and y'2-0.25 m2