Answer:
Concentration of ethanol required = 48.476 M
Explanation:
Given that:
the absorption intensity = 1.00
Molarity of ethanol = 1M
NMR instrument used = 160 MHz
Temperature used = 300 K
The required concentration of ethanol can be determined as follows:


= 48.476 M
The mass of NiCl₂•6HO₂ needed to prepare a 0.035 M 500 mL solution of NiCl₂•6HO₂ is 4.165 g
<h3>What is molarity? </h3>
This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
<h3>How to determine the mole of NiCl₂•6HO₂</h3>
- Molarity = 0.035 M
- Volume = 500 mL = 500 / 1000 = 0.5 L
Mole = Molarity × Volume
Mole of NiCl₂•6HO₂ = 0.035 × 0.5
Mole of NiCl₂•6HO₂ = 0.0175 mole
<h3>How to determine the mass of NiCl₂•6HO₂</h3>
- Mole of NiCl₂•6HO₂ = 0.0175 mole
- Molar mass of NiCl₂•6HO₂ = 238 g/mol
Mass = mole × molar mass
Mass of NiCl₂•6HO₂ = 0.0175 × 238
Mass of NiCl₂•6HO₂ = 4.165 g
Thus, 4.165 g of NiCl₂•6HO₂ is needed to prepare the solution
Learn more about molarity:
brainly.com/question/15370276
Answer:
The volume of the flask is<u> 20.245 litres .</u>
Explanation:
We are given with following information-
-------- 1
where R =
Molar mass of 
The given chemical equation is -
--------- 2
Now , calculation -
Mass of
formed = 118g
Molar mass of
= 
Mole = 
Therefore , moles of
formed = 
From equation 2 , we get to know that ,
2mole
formed from 5 mole 
Therefore ,
mole
formed from
mole 
Moles of
used =
R= 
Pressure (P)= 1.85atm
Temperature (T)= 322K
Moles of
(n)=
moles
Applying the formula above in 1 equation , that is
PV = nRT
putting the given values -

V = 20.245 litres.
Hence , the volume of the flask is <u>20.245 litres . </u>
At temperatures above 32°F (0°C), pure water ice melts and changes state from a solid to a liquid (water); 32°F (0°C) is the melting point. For most substances, the melting and freezing points are about the same temperature.
Hope i didn't give you to much info that all the info about ice melting.