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3 years ago

7

Bacteria are usually blank organism Pls help

2 answers:

DaniilM [7]3 years ago

8 0

Answer:

single-celled organisms

Explanation:

masha68 [24]3 years ago

3 0

I think the answer is -Microbes-

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In a light wave, which properties tell you the color of light

algol13

Answer :- In a light wave the property of wave which tells about the color of light is it's Wavelength .

Wavelength is the distance between one crest and one through , also it is the distance after which the wave repeat itself !

It's SI unit is meter !

It is scalar quantity !!

Different Wavelength of light have different color !!

• VIBGYOR

i.e, Violent , Indigo , Blue , Green , Yellow Orange, and Red along with their shades are the colors which we can see !!

• They almost range from 400nm to 700nm ( visible range of light )

4 0

3 years ago

When a chemical reaction creates a thin film outline of an anmial or plant what type of preservation has occured?

klasskru [66]

I believe carbonisation.

4 0

3 years ago

Excess aqueous copper(II) nitrate reacts with aqueous sodium sulfide to produce aqueous sodium nitrate and copper(II) sulfide as

nikitadnepr [17]

The question in incomplete, complete question is;

Determine the theoretical yield:

Excess aqueous copper(II) nitrate reacts with aqueous sodium sulfide to produce aqueous sodium nitrate and copper(II) sulfide as a precipitate. In this reaction 469 grams of copper(II) nitrate were combined with 156 grams of sodium sulfide to produce 272 grams of sodium nitrate.

Answer:

The theoretical yield of sodium nitrate is 340 grams.

Explanation:

$Cu(NO_3)_2(aq)+Na_2S(aq)\rightarrow 2NaNO_3(aq)+CuS(s)$

Moles of copper(II) nitrate = $\frac{469 g}{187.5 g/mol}=2.5013 mol$

Moles of sodium sulfide = $\frac{156 g}{78 g/mol}=2 mol$

According to reaction, 1 mole of copper (II) nitrate reacts with 1 mole of sodium sulfide.

Then 2 moles of sodium sulfide will react with:

$\frac{1}{1}\times 2mol= 2 mol$ of copper (II) nitrate

As we can see from this sodium sulfide is present in limiting amount, so the amount of sodium nitrate will depend upon moles of sodium sulfide.

According to reaction, 1 mole of sodium sulfide gives 2 mole of sodium nitrate, then 2 mole of sodium sulfide will give:

$\frac{2}{1}\times 2mol=4 mol$ sodium nitrate

Mass of 4 moles of sodium nitrate :

85 g/mol × 4 mol = 340 g

Theoretical yield of sodium nitrate = 340 g

The theoretical yield of sodium nitrate is 340 grams.

7 0

3 years ago

Read 2 more answers

0.7 L of H2 enters a reaction at standard temperature and pressure.

ASHA 777 [7]

Answer:

1.88 × 10²³ particles

Explanation:

Given data:

Volume of H₂ = 0.7 L

Number of particles at STP = ?

Solution:

First of all we will calculate the number of moles of H₂.

PV = nRT

n = PV / RT

n = 1 atm . 7 L / 0.0821 L. atm. mol⁻¹. k⁻¹ × 273.15 K

n = 7 atm. L / 22.43 L. atm. mol⁻¹

n = 0.312 mol

it is known that,

2 g H₂ = 1 mol = 6.022 × 10²³ particles

For 0.312 mol

0.312 × 6.022 × 10²³ particles

1.88 × 10²³ particles

6 0

3 years ago

For the reaction MgSO3(s) → MgO(s) + SO2(g), which is spontaneous only at high temperatures, one would predict thata. ΔH˚ is neg

Nataliya [291]

Answer: c. ΔH˚ is positive and ΔS˚ is positive

Explanation:

According to Gibb's equation:

$\Delta G=\Delta H-T\Delta S$

$\Delta G$ = Gibbs free energy

$\Delta H$ = enthalpy change

$\Delta S$ = entropy change

T = temperature in Kelvin

$\Delta G$ = +ve, reaction is non spontaneous

$\Delta G$ = -ve, reaction is spontaneous

$\Delta G$ = 0, reaction is in equilibrium

Thus for $\Delta G=-ve$

Case :

$T\Delta S$ > $\Delta H$

when $\Delta S\text{ and }\Delta H$ both have positive values.

$\Delta G=(+ve)-T(+ve)$

$\Delta G=(+ve)(-ve)=-ve$

Reaction is spontaneous only at at high temperatures.

8 0

4 years ago