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4 years ago

How do artificial reefs positively affect the ocean system

1 answer:

8 0

They provide a place for marine life to flourish, that would otherwise most-likely go extinct because of the constant decrease of natural reefs in our oceans.

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Pizza dough is topped with sauce, cheese, pepperoni, sausage, mushrooms, bell peppers, and olives. What type of mixture is this

Contact [7]

A slice of pizza is an example of a Heterogeneous mixture.

4 0

3 years ago

What is the [OH-] in a solution that has a [H3O+] = 1.0 x 10-6 M?

nika2105 [10]

Answer:

explanation

$kw = 1 \times {10}^{ - 14}$

$oh = {?}$

$h3o = 1.0 \times 10 {}^{ - 6}$

formula

$kw = h3o \times oh$

$insert \: values$

$1.0 \times 10 {}^{ - 14} = 1.0 \times {10}^{ - 6} \times oh$

$\frac{1.0 \times 10 {}^{ - 14} }{ 1.0 \times 10 {}^{ - 6} } = oh$

$1 \times {10}^{ - 8}$

7 0

3 years ago

Calculate the solubility of copper(II) hydroxide, Cu(OH)2, in g/L

Oduvanchick [21]

Answer:

Ksp = [ Cu+² ] [ OH-] ²

molar mass Cu(oH )2 ==> M= 63.546 (1) + 16 (2) + 1 (2) = 97.546 g/mol

Ksp = [ Cu+² ] [ OH-] ²

Ksp [ cu (OH)2 ] = 2.2 × 10-²⁰

|__________|___Cu+² __|_2OH-____|

|Initial concentration(M)|___0__|_0______|

|Change in concentration(M)|_+S |__+2S__|

|Equilibrium concentration(M)|_S _|2S___|

Ksp = [ Cu+² ] [ OH-] ²

2.2 ×10-²⁰ = (S)(2S)²= 4S³

$s = \sqrt[3]{ \frac{2.2 \times {10}^{ - 20} }{4} } = 1.8 \times {10}^{ - 7}$

S = 1.8 × 10-⁷ M

The molar solubility of Cu(OH)2 is 1.8 × 10-⁷ M

Solubility of Cu (OH)2 =

$Cu (OH)2 = \frac{1.8 \times {10}^{ - 7} mol \:Cu (OH)2 }{1L} \times \frac{97.546 \: g \: Cu (OH)2}{1 \: mol \: Cu (OH)2} \\ = 1.75428 \times 10 ^{ - 5}$

<h3>Solubility of Cu (OH)2 = 1.75428 × 10 -⁵ g/ L</h3>

I hope I helped you^_^

8 0

3 years ago

As the concentration of reacting particles increases, the rate of reaction generally

Veseljchak [2.6K]

Answer: increases

Explanation:the rate of reaction generally increases when the concentration is increased. Molecules have a better chance of having an effective collision that results in the reactions taking place

5 0

3 years ago

PLEASE HELP!!!

dmitriy555 [2]

Answer:

<h3>The answer is 2.90 L</h3>

Explanation:

In order to find the original pressure , we use the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the original volume

$V_1 = \frac{P_2V_2}{P_1} \\$

From the question

P1 = 250020 Pa

P2 = 120870 Pa

V2 = 6 L

We have

$V_1 = \frac{120870 \times 6}{250020} = \frac{725220}{250020} \\ = 2.90064794...$

We have the final answer as

Hope this helps you

5 0

4 years ago