Photosynthesis is the chemical process in which plants and other organisms

A scientist has isolated a fatty acid that has 26 carbons. most of the carbon atoms in the fatty acid chain are connected by sin

Shtirlitz [24]

Answer:
Based on giveninformation, the compound is a Poly Unsaturated fatty acid.

Explanation:
Fatty acids are carboxylic acids with -COOH functional group and a chain of hydrocarbons.

Fatty Acids are classified as,

i) Saturated Fatty Acids:
Those Fatty Acids in which there is no double bond between the carbon chain are called as saturated fatty acids.

Examples:
Lauric Acid CH₃(CH₂)₁₀COOH

Myristic Acid CH₃(CH₂)₁₂COOH

Palmitic Acid CH₃(CH₂)₁₄COOH

ii) Unsaturated Fatty Acids:
Those Fatty Acids in which contain a single double bond (mono-unsaturated) or more than one double bond (poly-unsaturated) d between the carbon atoms in a chain are called as unsaturated fatty acids.

Examples:
Linoleic acid

Vaccenic acid

Palmitoleic acid

The saturated fatty acid containing 26 carbon atoms is called as Cerotic acid. While cerotic acid containing a double bond at position 3 and 9 has a IUPAC name Hexacosa-3,9-dienoic acid with following structure.

3 0

3 years ago

What is the molar mass of magnesium

mina [271]

Hey there!

The molar mass of magnesium is 24.305 grams.

The molar mass of an element is the same as the atomic mass of an element, but measured in grams.

It's on the periodic table underneath the element symbol.

Hope this helps!

3 0

3 years ago

Complete the statement about the environment and its components.

borishaifa [10]

the environment is Healthy

3 0

3 years ago

Calculate E o , E, and ΔG for the following cell reactions (a) Mg(s) + Sn2+(aq) ⇌ Mg2+(aq) + Sn(s) where [Mg2+] = 0.025 M and [S

Rudik [331]

E⁰(cell) = 2.24V

E(cell) = 2.246V

∆G = -433 KJ/mol

Explanation:

Mg(s) + Sn²⁺(aq) ⇌ Mg²⁺(aq) + Sn(s)

[Mg2+] = 0.025 M

[Sn2+] = 0.040 M

First we need the standard reduction potentials:

. . . . . . . . . . . . . . . . . E°(V)

Mg²⁺ + 2 e⁻ ⇌ Mg(s). . .−2.372

Sn²⁺ + 2 e⁻ ⇌ Sn(s) . . . −0.13

Take the more negative (or less positive in other cases) one, and write it as an oxidation:

Mg(s) ⇌ Mg²⁺ + 2 e⁻. . .+2.372 V

Combine them,

Mg(s) + Sn²⁺ ⇌ Mg²⁺ + Sn(s)

E°(cell) = +2.372 – 0.13 V = 2.24 V

To get the cell potential under the conditions given, use the Nernst Equation:

E(cell) = E°(cell) – [(0.059)/n]•logQ = 2.24 V – 0.0295 V • log [Mg²⁺]/[Sn²⁺]

Note that the solids don't appear in Q, only the concs. of the dissolved ions.

E(cell) = 2.24 V – 0.0295 V X log (0.025)/(0.040)

= 2.24 + 0.006 V ≈ 2.246 V

The concentration ratio in Q (Sn²⁺ and Mg²⁺) is too close to 1 to shift E(cell) significantly from E°(cell) given the precision I have for the Sn reduction potential.

∆G = –nFE(cell) = –2(96.485 kJ/mol•V)(2.246 V) = –433 kJ/mol

E⁰(cell) = 2.24V

E(cell) = 2.246V

∆G = -433 KJ/mol

4 0

4 years ago

Moseley made revisions to the periodic table that resolved some of the problems with Mendeleev’s version. Which of these was a r

aalyn [17]

Since you provide no options, Henry Moseley measured a property linked to Periodic Table position. After his revisions to the periodic table, Atomic number became more meaningful and the three pair of elements that seemed to be in the wrong order could be explained

7 0

3 years ago

Read 2 more answers