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soldi70 [24.7K]
2 years ago
10

Photosynthesis is the chemical process in which plants and other organisms

Chemistry
1 answer:
-Dominant- [34]2 years ago
7 0

Answer:

sugar and oxygen

Explanation:

sugar (glucose) and oxygen

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The strength of an atom's attraction for the electrons in a chemical bond is the atom's?
Mazyrski [523]

<span><span>Yes. An element that is highly electronegative pulls more on the electrons in a bond, such as oxygen in H20. This creates a polar bond, where there is a small negative charge on the oxygen, and a small positive charge in between the hydrogens.

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3 years ago
PLZ HELP I WILL GIVE BRAINLY AND POINTS
max2010maxim [7]

Answer:

1. Define the problem

2. Conduct a literature search

3. Propose a hypothesis

4. Devise an experiment to prove or disprove

5. State conclusions

Explanation: In order to begin an experiment, you must first define a problem or question that you will be answering. Then you must research the problem in order to form a hypothesis, or an educated guess. Then you should devise and execute an experiment to answer your question. The conclusions that you draw will either prove or disprove your hypothesis. Hope this helps!

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3 years ago
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aleksandrvk [35]

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Explanation:

4 0
3 years ago
WILL GIVE BRAINLIST
8_murik_8 [283]
I would choose C bc if u look at it closely u can notice it goes up steadily and then BANG it decreases a lot
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3 years ago
Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.
Jlenok [28]

<u>Answer:</u> The density of gold in g/cm^3 is 19.22g/cm^3

<u>Explanation:</u>

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}

We are given:

Density of gold = 1200lb/ft^3

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into g/cm^3, we get:

\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3

Hence, the density of gold in g/cm^3 is 19.22g/cm^3

6 0
3 years ago
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