An object is dropped from the top of a 200 m tower. its height above the ground after t seconds is 200 - 4.9t^2. how fast fallin
1 answer:
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Answer:
a). 6 seconds
b). 12 seconds
c). 176.4 meters
Explanation:
a). Equation to be applied to calculate the time taken by the rocket to reach at the peak height,
v = u - gt
where v = final velocity
u = initial velocity = 58.8 m per sec
g = gravitational pull = 9.8 m per sec²
t = duration of the flight
At the peak height,
v = 0
Therefore, 0 = 58.8 - (9.8)(t)
t =
= 6 seconds
b). Total time of flight = 2(Time taken to go up)
= 2×6
= 12 sec
c). Formula to get the peak height is,
h = (58.8)6 -
= 352.8 - 176.4
= 176.4 meters