Answer:the force will remain same
Explanation:
because force is equal to the ratio of magnitude and distance
Answer:
B) The initial momentum is 12 kg*m/s, and the final momentum is 24 kg*m/s
Explanation:
The momentum of an object is given by the product between its mass (m) and its velocity (v):
Let's apply this formula to calculate the initial momentum and final momentum of the ball:
- initial momentum:
- Final momentum:
So, the correct answer is
B) The initial momentum is 12 kg*m/s, and the final momentum is 24 kg*m/s
The <u>speed</u> of the ride is
Speed = (distance covered) / (time to cover the distance)
Speed = (4,000 m) / (45 min)
Speed = <em>88.89 m/s</em>
Speed = <em>1.481 m/s</em>
Speed = <em>5.333 km/hr</em>
There's not enough information given in the question to calculate the velocity of the ride. For example ...
-- If the ride was completely in a straight line, then the velocity would be exactly equal to the speed.
-- If the rider went 2km from his house and then 2km back home again, his velocity for the whole ride would be zero.
We just don't know from the information given.
Answer:
2.82 s
Explanation:
The ball will be subject to the acceleration of gravity which can be considered constant. Therefore we can use the equation for uniformly accelerated movement:
Y(t) = Y0 + Vy0 * t + 1/2 * a * t^2
Y0 is the starting position, 2.3 m in this case.
Vy0 is the starting speed, 13 m/s.
a will be the acceleration of gravity, -9.81 m/s^2, negative because it points down.
Y(t) = 2.3 + 13 * t - 1/2 * 9.81 * t^2
It will reach the ground when Y(t) = 0
0 = 2.3 + 13 * t - 1/2 * 9.81 * t^2
-4.9 * t^2 + 13 * t + 2.3 = 0
Solving this equation electronically gives two results:
t1 = 2.82 s
t2 = -0.17 s
We disregard the negative solution. The ball spends 2.82 seconds in the air.
