The force is 2.0 N east
Explanation:
The impulse exerted by a force is defined as the product between the force itself and the time interval during which the force is applied. Mathematically, it is equal to the change in momentum experienced by the object on which the force is acting:

Where
I is the impulse
F is the force
is the time interval during which the force is applied
is the change in momentum
In this problem,
is the time interval
(east) is the impulse
Therefore, the magnitude of the force is

And the direction is the same as the impulse (east).
Learn more about impulse and change in momentum:
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So this is easy to calculate when you split the velocity into x and y components. The x component is going to equal cos(53) * 290 and the y component is going to equal sin(53)*290.
The x location therefore is 290*cos(53)*35 = 6108.4m
The y location needs to factor in the downwards acceleration of gravity too, which is 9.81m/s^2. We need the equation dist. = V initial*time + 0.5*acceleration*time^2.
This gives us d=290*sin(53)*35 + (0.5*-9.81*35^2)=2097.5m
So your (x,y) coordinates equals (6108.4, 2097.5)
Answer:
Ruko zara kuch Time dedo na please
Answer:
Acceleration of the crate is 0.362 m/s^2.
Explanation:
Given:
Mass of the box, m = 40 kg
Applied force, F = 15 N
Angle at which the force is applied,
= 15°
We have to find the magnitude of the acceleration.
Let the acceleration be "a".
FBD is attached with where we can see the horizontal and vertical component of force.
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and ⇒ 
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⇒ Applying concept of forces.
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<em> ...Newtons second law Fnet = ma</em>
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⇒ Plugging the values.
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<em>...f is the friction which is zero here.</em>
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Magnitude of the acceleration of the crate is 0.362 m/s^2.