It really depends on your options.
Since NH3 solution is a weak base, the option that neutralizes a base is an acid. So find an acid among your options, and here are some examples: HNO3, HCl, etc.
2 1^/4 + 11^/2 = 9^/4 + 3^/2 = 9^/4 + 6^/4 = 15^/4 = 3 3^/4
1) (C2H5)2CBrCH2CH3 is the answer
explaiation:-
so when HBr is added to an alkene , according to the Markonicoff's rule ...H atoms are bonded to the C containing the most amount of H and Br is added to the other C.
2) Just add alkoholic KOH∆
Answer:
30.3 g
Explanation:
At STP, 1 mol of any gas will occupy 22.4 L.
With the information above in mind, we <u>calculate how many moles are there in 32.0 L</u>:
- 32.0 L ÷ 22.4 L/mol = 1.43 mol
Then we <u>calculate how many moles would there be in 16.6 L</u>:
- 16.6 L ÷ 22.4 L/mol = 0.741 mol
The <u>difference in moles is</u>:
- 1.43 mol - 0.741 mol = 0.689 mol
Finally we <u>convert 0.689 moles of CO₂ into grams</u>, using its <em>molar mass</em>:
- 0.689 mol * 44 g/mol = 30.3 g
