<u>Answer:</u>
<u>For 3:</u> The total mass change of the reaction is 
<u>For 4:</u> The mass defect is
and energy equivalent to this mass is 
<u>For 5:</u> The equivalent mass of the reaction is 
<u>Explanation:</u>
To calculate the mass change of the reaction for given energy released, we use Einstein's equation:

E = Energy released = 
= mass change = ?
c = speed of light = 
Putting values in above equation, we get:

Hence, the total mass change of the reaction is 
For the given isotopic representation: 
Atomic number = Number of protons = 27
Mass number = 60
Number of neutrons = Mass number - Atomic number = 60 - 27 = 33
To calculate the mass defect of the nucleus, we use the equation:
where,
= number of protons = 27
= mass of one proton = 1.00728 amu
= number of neutrons = 33
= mass of one neutron = 1.00867 amu
M = Nuclear mass number = 59.9338 amu
Putting values in above equation, we get:
![\Delta m=[(27\times 1.00728)+(33\times 1.00867)]-[59.9338]\\\\\Delta m=0.54887amu](https://tex.z-dn.net/?f=%5CDelta%20m%3D%5B%2827%5Ctimes%201.00728%29%2B%2833%5Ctimes%201.00867%29%5D-%5B59.9338%5D%5C%5C%5C%5C%5CDelta%20m%3D0.54887amu)
Converting the value of amu into kilograms, we use the conversion factor:
So, 
To calculate the equivalent energy, we use the equation:

E = Energy released = ?
= mass change = 
c = speed of light = 
Putting values in above equation, we get:

Converting this into kilojoules, we use the conversion factor:
1 kJ = 1000 J
So, 
Hence, the mass defect is
and energy equivalent to this mass is 
For the given chemical reaction:

To calculate the equivalent mass of the reaction for given energy released, we use Einstein's equation:

E = Energy released = 
= mass change = ?
c = speed of light = 
Putting values in above equation, we get:

Hence, the equivalent mass of the reaction is 