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lapo4ka [179]
3 years ago
15

An engineer is surveying a building with a device that is 5 feet above the ground. He is 50 feet from the building and is lookin

g with an angle of elevation of 50°. How tall is the building?

Mathematics
1 answer:
dolphi86 [110]3 years ago
5 0
1. Check the sketch of the problem.

2. In right triangle DCE,

 tan50= \frac{EC}{DC}= \frac{x}{50}

tan 50 can be found to be 1.19 using a scientific calculator or other software.

1.19=\frac{x}{50}

x=1.19*50=59.5 (feet)

3. The height of the building is 59.5+5=64.5 (feet)

Answer: 64.5 (feet)

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