Answer:
2.765amu is the contribution of the X-19 isotope to the weighted average
Explanation:
The average molar mass is defined as the sum of the molar mass of each isotope times its abundance. For the unknown element X that has 2 isotopes the weighted average is defined as:
X = Mass X-19 * Abundance X-19 + MassX-21 * Abundance X-21
The contribution of the X-19 isotope is its mass (19.00 amu) times its abundance (14.55% = 0.1455). That is:
19.00amu * 0.1455 =
2.765amu is the contribution of the X-19 isotope to the weighted average
135.1kPa
Explanation:
Given parameters:
T1 = 27°C
P1 = 101.325 kPa
T2 = 127°C
Unknown:
P2 = ?
Solution:
Using a derivative of the combined gas law where we assume that the gas has a constant volume, we can solve for the unknown.
At constant volume:
P1 is the initial pressure
T1 is the initial temperature
P2 is the final pressure
T2 is the final temperature
Take the given temperature to K
T1 = 27 + 273 = 300K
T2 = 127 + 273 = 400K
Input the variables:
P2 = 135.1kPa
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Boyle's law brainly.com/question/8928288
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Answer:
Player B
Explanation:
I just did it and I got it right :)
There are two molecular orbitals in the CH2O or formaldehyde. These are designated by the two types of bonding involved. The first is the sigma bonding. It is the head-on overlap of electrons of the C and H atoms. The second molecular orbital is formed from the pi orbital bonding. This is a sideway overlap of electrons between C-O bonding.
Answer:
[KOH] = 0.10M in KOH
Explanation:
Molar Concentration [M] = moles solute/volume solution in liters
moles KOH = 0.56g/56g/mole = 0.01mole
Volume of solution = 100cm³ = 100ml = 0.10 liter
[KOH] = 0.01 mole KOH / 0.10 liter solution = 0.10M in KOH
