a. 48.6 is magnesium and 32.0 is oxygen
b. 80.6
c. also 80.6
d. yes, because the product has equal mass to the reactants
8.908 G/cm^3 is the density of a nickel
Answer:
The answer is "
".
Explanation:
Please find the complete question in the attached file.
Total Moles of
= moles of
![= \frac{mass}{molar \ mass \ of MgSO_4}\\\\= \frac{0.450}{120.37}\\\\ = 0.0037385 \ mol](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7Bmass%7D%7Bmolar%20%5C%20mass%20%5C%20of%20MgSO_4%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B0.450%7D%7B120.37%7D%5C%5C%5C%5C%20%3D%200.0037385%20%5C%20mol)
![Mg_2^{+} + EDTA4^{-} \longrightarrow Mg(EDTA)2^{-}](https://tex.z-dn.net/?f=Mg_2%5E%7B%2B%7D%20%2B%20EDTA4%5E%7B-%7D%20%5Clongrightarrow%20%20Mg%28EDTA%292%5E%7B-%7D)
EDTA mol in 37.6 mL of solution = 50.0 mL of ![Mg2^{+}](https://tex.z-dn.net/?f=Mg2%5E%7B%2B%7D)
total moles of ![Mg2^{+}](https://tex.z-dn.net/?f=Mg2%5E%7B%2B%7D)
![= \frac{50.0}{500} \times 0.0037385\\\\= 3.7385 \times 10^{(-4)} \ mol\\](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B50.0%7D%7B500%7D%20%5Ctimes%20%200.0037385%5C%5C%5C%5C%3D%203.7385%20%5Ctimes%20%2010%5E%7B%28-4%29%7D%20%5C%20%20mol%5C%5C)
![Ca2^{+} + EDTA4^{-} \longrightarrow Ca(EDTA)2^{-}](https://tex.z-dn.net/?f=Ca2%5E%7B%2B%7D%20%2B%20EDTA4%5E%7B-%7D%20%5Clongrightarrow%20Ca%28EDTA%292%5E%7B-%7D)
EDTA moles in a solution of 1.40 mL
the solution of EDTA moles.
![= \frac{1.40}{37.6} \times 3.7385 \times 10^{(-4)} \\\\= 1.392 \times 10^{(-5)}\ mol\\\\](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B1.40%7D%7B37.6%7D%20%5Ctimes%20%203.7385%20%5Ctimes%20%2010%5E%7B%28-4%29%7D%20%5C%5C%5C%5C%3D%201.392%20%5Ctimes%20%2010%5E%7B%28-5%29%7D%5C%20%20mol%5C%5C%5C%5C)
Mass of
mole
the molar mass of
![= 1.392 \times 10^{(-5)} \times 100.09\\\\= 0.00139 \ g\\\\ = 1.39 \ mg](https://tex.z-dn.net/?f=%3D%201.392%20%5Ctimes%2010%5E%7B%28-5%29%7D%20%5Ctimes%20100.09%5C%5C%5C%5C%3D%200.00139%20%5C%20g%5C%5C%5C%5C%20%3D%201.39%20%5C%20mg)
Answer:
Mass of Nacl = 4.92 gram (Approx)
Explanation:
Given:
Hydrochloric acid = 3.3 g
Sodium hydroxide = 5 g
Computation:
Hcl + NaoH ⇒ Nacl + H₂O
Number of mole of Hcl = 3.3 / 36.46 = 0.0905 moles
Number of mole of NaoH = 5 / 40 = 0.125 moles
We, know that number of moles in Hcl is less then number of mole in NaoH
So,
Number of mole of Hcl = Number of mole of Nacl
So,
Mass of Nacl = Number of mole of Nacl × Molar mass of Nacl
Mass of Nacl = 0.0905 × 54.4
Mass of Nacl = 4.92 gram (Approx)