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Jet001 [13]
2 years ago
15

Brainliest if correct Question 7 of 10

Physics
2 answers:
RoseWind [281]2 years ago
6 0
The answer is A I think
OleMash [197]2 years ago
4 0

Answer:

I would think A

Explanation:

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A body weighs 100newtons and 80newtons when submerged in water.calculate the upthrust action on the body
katovenus [111]

Answer:

20 N

Explanation:

In air, the normal force is equal to the weight.

∑F = ma

N − mg = 0

N = mg

Submerged in water, the normal force is equal to the weight minus the buoyant force:

∑F = ma

B + N − mg = 0

N = mg − B

Plugging in values:

80 N = 100 N − B

B = 20 N

3 0
3 years ago
Which of the following statements is true?
kupik [55]

Answer:

2. The hydrogen atom has quantized energy levels.

Explanation:

The Bohr model of the atom states that the structure of the atom is quantized, that is, that electrons can only orbit the nucleus in specific orbits with a fixed radius. Therefore, the electron cannot be in energy levels that do not correspond to these quantized levels.

4 0
3 years ago
a 0.0780 kg lemming runs off a 5.36 m high cliff at 4.84 m/s. what is its kinetic energy when it's 2.00 m above the ground
Blababa [14]

Answer:

KE_2 = 3.48J

Explanation:

Conservation of Energy

E_1 = E_2

PE_1+KE_1 = PE_2+KE_2

m*g*h+(1/2)m*v² = m*g*h+(1/2)m*v²

(0.0780kg)*(9.81m/s²)*(5.36m)+(.5)*(0.0780kg)*(4.84m/s)² = (0.0780kg)*(9.81m/s²)*(2m)+KE_2

4.10J+0.914J = 1.53J + KE_2

5.01J = 1.53J + KE_2

KE_2 = 3.48J

3 0
3 years ago
If you heat a thin, circular ring in the oven, does the rings hole get larger or smaller?
KiRa [710]
Unless the ring by design will have restriction for any outward expansion. The hole will get larger / bigger as you heat this up. The more you heat an object the more it expands, thus the larger the hole gets. The only case is when outward expansion is restricted, the expansion will be inward as it is the only direction the ring can expand to.
5 0
2 years ago
An object is moving at a velocity of 23 m/s. It accelerates to a velocity of 85 m/s over a time of 8.3 s. What acceleration did
Bess [88]
\frac{v \: final \: - v \: initial }{time} = \: a
\\ \frac{85 - 23}{8.3} = 7.467 \: \frac{m}{ {s}^{2} }
7 0
3 years ago
Read 2 more answers
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