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3 years ago

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8 Write the equation

1 answer:

MAVERICK [17]3 years ago

6 0

Answer:

Explanation — This page looks at the oxidation of alcohols using acidified sodium or ... of sodium or potassium dichromate(VI) acidified with dilute sulfuric acid. ... The electron-half-equation for this reaction is as follows: ... To do that, oxygen from an oxidizing agent is represented as [O]. ... Article type: Section or Page.

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You are sitting outside on a warm day with a cold glass of water. You notice water droplets starting to collect on the outside o

Katarina [22]

Answer:

2

Explanation:

3 0

3 years ago

Read 2 more answers

Write the 1 g equivalents using the following prefixes: (a) mega−, (b) kilo−, (c) deci−, (d) centi−, (e) milli−, (f) micro−, (g)

dem82 [27]

<u>Explanation:</u>

Unit is defined as the quantity that is used as a standard for measurement.

S.I. unit of mass of kilograms. Other units in which mass of a substance can be measured are grams, milligrams, etc...

All these units are inter convertible.

<u>For a:</u> Mega-

The conversion factor used is:

$1g=10^{-6}Mg$

<u>For b:</u> kilo-

The conversion factor used is:

$1g=10^{-3}kg$

<u>For c:</u> deci-

The conversion factor used is:

$1g=10dg$

<u>For d:</u> centi-

The conversion factor used is:

$1g=10^{3}cg$

<u>For e:</u> milli-

The conversion factor used is:

$1g=10^3mg$

<u>For f:</u> micro-

The conversion factor used is:

$1g=10^6\mu g$

<u>For g:</u> nano-

The conversion factor used is:

$1g=10^9ng$

<u>For h:</u> pico-

The conversion factor used is:

$1g=10^{12}pg$

8 0

3 years ago

What is the Anion and it’s charge.

Dafna11 [192]

Answer:

anion has a negative charge

An anion has more electrons than protons, consequently giving it a net negative charge

8 0

3 years ago

A 2.10g of unknown monoprotic acid is titrated with 38.10 mL of .265M NaOH. Calculate the molar mass of the ac? I already calcul

Shkiper50 [21]

$V_{NaOH}=38,1mL=0,0381L\\
C_{m}=0,265M\\\\
n=C_{m}*V=0,265\frac{mol}{L}*0,0381L\approx0,0101mol$

HR + NaOH ⇒ NaR + H₂O
1mol : 1mol

$0,0101mol \ \ \ \ \Rightarrow \ \ \ \ 2,1g\\
1mol \ \ \ \ \ \ \ \ \ \ \Rightarrow \ \ \ m\\\\
m=\frac{1mol*2,1g}{0,0101mol}\approx 207,92g\\\\
M_{HR}=207,92\frac{g}{mol}$

5 0

3 years ago

How many moles of sodium are present in 17 g of Na?

11Alexandr11 [23.1K]

Answer:

1. 0.74mol

2. 0.42mol

3. 2.125mol

4. 0.301mol

5. 4.52 × 10^23 particles

Explanation:

Number of moles (n) in a substance can be found using the formula:

mole (n) = mass/molar mass

Using this formula, the following moles are calculated:

1. Molar of Na = 23g/mol

mole = 17/23

mole = 0.74mol

2. Molar mass of Na2SO4 = 23(2) + 32 + 16(4)

= 46 + 32 + 64

= 142g/mol

Mole = 60/142

mole = 0.42mol

3. Molar mass of CO2 = 12 + 16(2)

= 12 + 32

= 44g/mol

mole = 93.5/44

mole = 2.125mol

4. Molar mass of sodium nitrate (NaNO3) = 23 + 14 + 16(3)

= 23 + 14 + 48

= 85g/mol

mole = 25.6/85

mole = 0.301mol

5. Number of particles in one mole of a substance is 6.022 × 10^23 particles. Hence, in 0.75mol of calcium hydroxide (Ca(OH)2, there will be;

0.75mol × 6.02 × 10^23

= 4.515 × 10^23

= 4.52 × 10^23 particles

8 0

3 years ago