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den301095 [7]
3 years ago
6

Which planet orbits in a different plane than all of the others?

Physics
1 answer:
coldgirl [10]3 years ago
6 0

Although they're all 'close', none of the planets orbits in the same plane as any other planet.  They're all in slightly different planes.

The farthest out compared to all the others is Pluto, with an orbit inclined about 17 degrees compared to the ecliptic plane (Earth's orbit).  But Pluto is officially not a planet, so I don't think it's a good answer.

The next greatest inclination compared to Earth's orbit is <em>Mercury</em>.  That one is about 7 degrees.

The other six planets are all in different orbital planes inclined less than 7 degrees compared to Earth's orbit.

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How do hydrogen bonds affect boiling points?
Yuri [45]

Boiling points are raised by hydrogen bonds because they make different molecules desire to "attach" to one another, which requires more energy to do so. In water, for instance, the hydrogen proton is in a state that resembles ionization because the connections between oxygen and hydrogen, while covalent, are strongly polar. The oxygen also receives a partial negative charge. Therefore, hydrogen bonds are formed when the electro-positive H in one molecule is strongly electrostatically attracted to the electro-negative O in nearby molecules. Despite being weak links, they are powerful enough to significantly alter the liquid's characteristics.  

Thanks!

>> ROR

8 0
2 years ago
Your roommate leaves a 120W fan running in your apartment.Over the course of an hour,how much thermal energy does the fan add to
zubka84 [21]

Answer:

4.32\cdot 10^5 J

Explanation:

Power is related to energy by the following relationship:

P=\frac{E}{t}

where

P is the power used

E is the energy used

t is the time elapsed

In this problem, we know that

- the power of the fan is P = 120 W

- the fan has been running for one hour, which corresponds to a time of

t = 1 h \cdot (60 min/h)(60 s/min)=3600 s

So we can re-arrange the previous equation to find E, the energy (in the form of thermal energy) released by the fan:

E=Pt=(120 W)(3600 s)=4.32\cdot 10^5 J

3 0
3 years ago
Read 2 more answers
Can someone answer this question?<br><br><br><br><br><br><br> {For me: question 48}
qaws [65]
0.000000218 = 2 x 10^ -8
4 0
3 years ago
Sunlight strikes a solar panel, which is then used to power the lights in a
Stells [14]

Answer:

B

Explanation:

Sunlight comes in the form of light energy. Upon striking the solar panels, it converts the light energy into electrical energy so as to run throughout the circuits. Then since it's used to power light, the electrical energy will be converted back into light energy

7 0
3 years ago
Read 2 more answers
Can someone solve this problem and explain to me how you got it​
evablogger [386]

Answer:

question5: F=74312.5N

question6: charge at the end of antenna=0.37N

Explanation:

Coulomb's law: the magnitude of the force of attraction or repulsion due to two charges is proportional to the product of the magnitude of the charges and inversely proportional to the square of distance between the charges.

⇒F\alpha\frac{q1*q2}{r^{2}}

∴F=k\frac{q1*q2}{r^{2}}

where F is the force of attraction or repulsion

k is Coulumb's constant=9*10^{9}Nm^{2}C^{-2}

q1 and q2 are the magnitude of the charges

r is the distance between two charges

The force between the two charges is attractive if they are of different polarity

The force between the two charges is repulsive if they are of same polarity

Question5:

Given: q1=0.041 C, q2=0.029 C, r=12 m

therefore by Coulumb's law,

F=9*10^{9}*\frac{0.041*0.029}{12^{2}}

F=74312.5N

Question6:

Given: q1=3*10^{-18}C, r=5 m, F=4*10^{-11}N

therefore by Coulumb's law,

4*10^{-11}=9*10^{9}*\frac{3*10^{-18}*q2}{5^{2}}

⇒q2=\frac{4*10^{-11}*25}{9*10^{9}*3*10^{-18}} \\=0.37C

4 0
3 years ago
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