Answer:mile
Explanation: heres a hint think aboyt the distance between your house to school
Answer:
BC and DE
Explanation:
In the given figure, the velocity time graph is shown. We know that the area under v-t curve gives the displacement of the particle.
Area under AB, ![d_1=\dfrac{1}{2}\times 2\times 10=10\ m](https://tex.z-dn.net/?f=d_1%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%202%5Ctimes%2010%3D10%5C%20m)
Area under BC, ![d_2=\dfrac{1}{2}\times 2\times 4=4\ m](https://tex.z-dn.net/?f=d_2%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%202%5Ctimes%204%3D4%5C%20m)
Area under CD, ![d_3=\dfrac{1}{2}\times 2\times 7=7\ m](https://tex.z-dn.net/?f=d_3%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%202%5Ctimes%207%3D7%5C%20m)
Area under DE, ![d_4=\dfrac{1}{2}\times 2\times 4=4\ m](https://tex.z-dn.net/?f=d_4%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%202%5Ctimes%204%3D4%5C%20m)
Area under EF, ![d_5=\dfrac{1}{2}\times 2\times 3=3\ m](https://tex.z-dn.net/?f=d_5%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%202%5Ctimes%203%3D3%5C%20m)
So, form above calculations it is clear that, during BC and DE undergo equal displacement. Hence, the correct option is (c) "BC and DE = 4 meters".
To solve the exercise it is necessary to take into account the concepts of wavelength as a function of speed.
From the definition we know that the wavelength is described under the equation,
![\lambda = \frac{c}{f}](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7Bc%7D%7Bf%7D)
Where,
c = Speed of light (vacuum)
f = frequency
Our values are,
![f = 2Hz](https://tex.z-dn.net/?f=f%20%3D%202Hz)
![c = 3*10^8km/s](https://tex.z-dn.net/?f=c%20%3D%203%2A10%5E8km%2Fs)
Replacing we have,
![\lambda = \frac{c}{f}](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7Bc%7D%7Bf%7D)
![\lambda = \frac{3*10^8km/s}{2Hz}](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7B3%2A10%5E8km%2Fs%7D%7B2Hz%7D)
![\lambda = 1.5*10^8m](https://tex.z-dn.net/?f=%5Clambda%20%3D%201.5%2A10%5E8m)
<em>Therefore the wavelength of this wave is
</em>
The force applied to the cannonball and cannon is equal. The explosion inside the cannon will generate a pressure which will turn into a force on both cannonball and cannon. The cannon being heavier and fixed to the ground will move a bit, but the cannonball will be thrown away, fired.
Answer:
![d_1 = 16 d](https://tex.z-dn.net/?f=d_1%20%3D%2016%20d)
Explanation:
As we know that initial speed of the fall of the stone is ZERO
![v_i = 0](https://tex.z-dn.net/?f=v_i%20%3D%200)
also the acceleration due to gravity on Mars is g
so we have
![d = v_i t + \frac{1}{2}gt^2](https://tex.z-dn.net/?f=d%20%3D%20v_i%20t%20%2B%20%5Cfrac%7B1%7D%7B2%7Dgt%5E2)
now we have
![d = 0 + \frac{1}{2}g t^2](https://tex.z-dn.net/?f=d%20%3D%200%20%2B%20%5Cfrac%7B1%7D%7B2%7Dg%20t%5E2)
now if the same is dropped for 4t seconds of time
then again we will use above equation
![d_1 = 0 + \frac{1}{2}g(4t)^2](https://tex.z-dn.net/?f=d_1%20%3D%200%20%2B%20%5Cfrac%7B1%7D%7B2%7Dg%284t%29%5E2)
![d_1 = 16(\frac{1}{2}gt^2)](https://tex.z-dn.net/?f=d_1%20%3D%2016%28%5Cfrac%7B1%7D%7B2%7Dgt%5E2%29)
![d_1 = 16 d](https://tex.z-dn.net/?f=d_1%20%3D%2016%20d)