Given:
P1 = 400 kPa
T1 = 110 K
T2 = 235K
Required:
P2
Solution:
Apply Gay-Lussac’s
law where P/T = constant
P1/T1 = P2/T2
P2 = T2P1/T1
P2 = (235K)(400kPa)
/ (110K)
P2 = 855 kPa
Large global wind systems are created by the uneven heating of the Earth's surface. Warm air rises at the equator and moves toward the poles. At the poles, the cooler air sinks and moves back toward the equator.
The frequency heard by the moth is the frequency emitted by the bat by virtue of its speed; 38.0kHz. B) If the speed of the bat is increased, the frequency heard by the moth is higher.
<h3>What is the frequency heard by the moth?</h3>
It follows from the task content that the frequency of the emitted by the bat is heard by the moth and hence, the frequency heard by the moth is; 38kHz.
B) Since, the speed and frequency of sound waves are directly proportional, speed = wavelength × frequency; it therefore follows that when the speed of the bat is increased, the frequency heard by the moth is higher.
Read more on speed and frequency;
brainly.com/question/10728818
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Answer:
A, True.
Explanation:
A heat engine converts heat into mechanical energy.
