A 0.0010-kg pellet is fired at a speed of 50.0m/s at a motionless 0.35-kg piece of balsa wood. When the
2 answers:
Answer: The pellet and wood slide at a speed of 0.142 m/s.
Explanation:
To calculate the velocity of the pellet and wood after the collision, we use the equation of law of conservation of momentum, which is:
where,
= mass of pellet = 0.001kg
= Initial velocity of pellet = 50m/s
= Final velocity of pellet = v m/s
= mass of wood = 0.36kg
= Initial velocity of wood = 0m/s
= Final velocity of wood = v m/s
Putting values in above equation, we get:
Hence, the pellet and wood slide at a speed of 0.142 m/s.
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Given:
heat generated by John's cooling system, = 45 W (1)
If ρ, A, and v corresponds to John's cooling system then let be the variables for Mike's system then:
Formula use:
Heat generated,
where,
= density
A = area
v = velocity
Solution:
for Mike's cooling system:
=
⇒ =
× A ×
= 4.513
A
Using eqn (1) in the above eqn, we get:
= 4.513 × 45 = 203.09 W
Answer:
The value of the potential energy of the particle at point B is 85 joules.
Explanation:
According to the Principle of Energy Conservation, the energy cannot be created nor destroyed, only transformed. The particle at point A has kinetic and potential energy and receives a work due to an external conservative force (Work-Energy Theorem), whose sum is equal to potential energy at point B. Mathematically speaking, the expression that describes the phenomenon is:
Where:
- Kinetic energy at point A, measured in joules.
- Potential energy at point A, measured in joules.
- Work due to conservative force from A to B, measured in joules.
- Potential energy at point B, measured in joules.
The initial kinetic energy of the particle is:
Where:
- Mass, measured in kilograms.
- Velocity, measured in meters per second.
If and
, then:
Finally, the value of the potential energy at point B is:
The value of the potential energy of the particle at point B is 85 joules.