Question

A car travels 20 km west and then 20 km south. what is the magnitude of its displacement vector

Answer 1

Answer:

the magnitude of displacement vector is 28.28 km.

Explanation:

It is given that,

Distance covered by the car, $d_1=20\ km$ (due west)

Distance covered by the car, $d_2=20\ km$ (due south)

Let d is the displacement vector of the car. We know that the shortest path covered by an object is called its displacement. In this case, the magnitude of its displacement vector is given by :

$d=\sqrt{d_1^2+d_2^2}$

$d=\sqrt{(20)^2+(20)^2}$

d = 28.28 km

So, the magnitude of its displacement vector is 28.28 km. Hence, this is the required solution.

Answer 2

A^2 + b^2=c^2 
that is how to find magnitude
xcos0=20cos180
ycos0=20sin270
that should give you the vectors 
and your answer should state the quadrant degree which it is in and vector and direction it is in like west,south