Answer:
Limiting reactant = B2O3
Amount of BCl3 formed = 468 g
Explanation:
The given reaction is:
In order to identify the limiting reagent calculate the moles of B2O3, C and Cl2. The reagent with the lowest moles is the limiting reactant
Since the moles of B2O3 < C < Cl2, the limiting reactant is B2O3
Based on the reaction stoichiometry:
1 mole of B2O3 produces 2 moles of BCl3
Hence, the number of moles of BCl3 produced under the experimental conditions = 2*1.997=3.994 moles
Answer:
The number of moles of the chemical constituents will be less than the actual amount.
Explanation:
In calculating empirical formula, we begin with the number of grams of each element, given in the problem.
Given that the spill will affect the mass concentration of the copper chloride solution, calculations to determine the molecular formula (using Molarity = mass conc ÷ molecular mass ) would give a lesser result, which would in turn lower the number of moles of the copper and chloride in the empirical formula calculation.
Answer:
synthesis reaction
The chemical reaction 2H2+O2→2H2O 2 H 2 + O 2 → 2 H 2 O is classified as a synthesis reaction
Answer:
Melting point is the temperature at which solid and liquid phases of a substance are in equilibrium.
Boiling point is the temperature at which its vapour pressure is equal to the external pressure.
