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Arte-miy333 [17]
3 years ago
11

What is the distance between points P(7, -2) and Q(-5, -1)?

Mathematics
1 answer:
amid [387]3 years ago
7 0
distance= \sqrt{(7-(-5))^2+(-2-(-1))^2}= \\ \\ =  \sqrt{12^2+(-1)^2}= \sqrt{145}   \approx12.04
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Answer:

<h2>50.8°</h2>

Step-by-step explanation:

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2√15² = 2√6² + b²

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Subtract 24

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Now, that we have all three sides, we will use the law of cosines to figure out the angle.

c² = a² + b² - 2abCosC°

Substitute the values in.

6² = 2√15² + 2√6² - 2(2√15)(2√6)CosC°

36 = 60 + 24 - 2(37.947331922)CosC°

36 = 60 + 24 - 75.894663844CosC°

36 = 84 - 75.894663844CosC°

Subtract 84

-48 = -75.9CosC°

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Arccos (0.63241106719) = 50.77176844°

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