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mestny [16]
3 years ago
15

A 0.023 kg golf ball moving at 18.9 m/s crashes through the window of a house in 5.4 × 10−4 s. After the crash, the ball contin-

ues in the same direction with a speed of 10.1 m/s.
Assuming the force exerted on the ball by the window was constant, what was the mag- nitude of this force?
Answer in units of N.
Physics
1 answer:
PolarNik [594]3 years ago
7 0
Force can be expressed as the time-rate change of momentum

Mathematically, Force = Change in momentum/change in time

Change in momentum = m(10.1-18.9) = -0.2024

Force = -2024/5.4 = -375N(approx)

The significance of the '-' sign is that the direction of force is the opposite that of the direction of our velocities since we assumed them to be positive.

Also this is the force on the ball, the force on the window will be equal and opposite.
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sonic is sliding down a frictionless 15m tall hill. He starts at the top with a velocity of 10m/s. At the bottom of the hill he
podryga [215]

Answer:

The maximum speed of sonic at the bottom of the hill is equal to 19.85m/s and the spring constant of the spring is equal to (497.4xmass of sonic) N/m

Energy approach has been used to sole the problem.

The points of interest for the analysis of the problem are point 1 the top of the hill and point 2 the bottom of the hill just before hitting the spring

The maximum velocity of sonic is independent of the his mass or the geometry. It is only depends on the vertical distance involved

Explanation:

The step by step solution to the problem can be found in the attachment below. The principle of energy conservation has been applied to solve the problem. This means that if energy disappears in one form it will appear in another.

As in this problem, the potential and kinetic energy at the top of the hill were converted to only kinetic energy at the bottom of the hill. This kinetic energy too got converted into elastic potential energy .

x = compression of the spring = 0.89

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A scuba diver sees light reflected from the water’s surface. show answer No Attempt If the index of refraction for air is 1.00 a
sasho [114]

Answer:

53.06°

Explanation:

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Let the angle of polarisation is ip.

Use Brewster's law,

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thus, the angle of polarisation is  53.06°.

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Answer:

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