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3 years ago

15

Screws and wedges are modified blank

1 answer:

4vir4ik [10]3 years ago

8 0

This is what I know
<span>Splitting securing A wedge is a triangular shaped tool, a compound and portable inclined plane, and one of the six classical simple machines. </span>

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Brainliest for the first person to answer Which is a characteristic of an electromagnetic wave?

KiRa [710]

The first one. The E and B chatacteristic are perpendicular to eachother. The direction of the wave can be found by the right hand rule.

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3 years ago

A 16.2 kg person climbs up a uniform ladder with negligible mass. The upper end of the ladder rests on a frictionless wall. The

S_A_V [24]

To solve this problem we will apply the concepts related to the balance of forces. We will decompose the forces in the vertical and horizontal sense, and at the same time, we will perform summation of torques to eliminate some variables and obtain a system of equations that allow us to obtain the angle.

The forces in the vertical direction would be,

$\sum F_x = 0$

$f-N_w = 0$

$N_w = f$

The forces in the horizontal direction would be,

$\sum F_y = 0$

$N_f -W =0$

$N_f = W$

The sum of Torques at equilibrium,

$\sum \tau = 0$

$Wdcos\theta - N_wLsin\theta = 0$

$WdCos\theta = fLSin\theta$

$f = \frac{Wd}{Ltan\theta}$

The maximum friction force would be equivalent to the coefficient of friction by the person, but at the same time to the expression previously found, therefore

$f_{max} = \mu W=\frac{Wd}{Ltan\theta}$

$\theta = tan^{-1} (\frac{d}{\mu L})$

Replacing,

$\theta = tan^{-1} (\frac{0.9}{0.42*2})$

$\theta = 46.975\°$

Therefore the minimum angle that the person can reach is 46.9°

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3 years ago

7. A 50 kg pole vaulter running at 10 m/s vaults over the bar. Her speed when she is over the bar is 1.0 m/s. Neglect air resist

luda_lava [24]

Answer: 5.05 m

Explanation:

4 0

3 years ago

Read 2 more answers

Henrietta is going off to her physics class, jogging down the sidewalk at a speed of 2.70 m/s. Her husband Bruce suddenly realiz

Katen [24]

Answer:

The velocity is $v = 6.66 \ m/s$

Henrietta is at distance $s= 18.17 \ m$ from the under the window

Explanation:

From the question we are told that

The speed of Henrietta is $v= 2.70 \ m/s$

The height of the window from the ground is $h = 36.5 \ m$

Generally the time taken for the lunch to reach the ground assuming it fell directly under the window is

$t = \sqrt{\frac{2 * h }{g} }$

=> $t = \sqrt{\frac{2 * 36.5 }{9,8} }$

=> $t = 2.73 \ s$

Generally the time taken for the lunch to reach Henrietta is mathematically represented as

$T = t + t_1$

Here $t_1$ is the time duration that elapsed after Henrietta has passed below the window the value is given as 4 s

Now

$T = 2.73 + 4$

=> $T = 6.73 \ s$

Generally the distance covered by Henrietta before catching her lunch is

$s= v * T$

=> $s= 2.70 * 6.73$

=> $s= 18.17 \ m$

Generally the speed with which Bruce threw her lunch is mathematically represented as

$v = \frac{18.17}{2.73}$

$v = 6.66 \ m/s$

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3 years ago

If a bottlel filled with water 25c and freezes at -5c the waters tempreture drop what is the sign of the systems q,w,ΔE

laila [671]

Triangle because h2o and celsious have yhree silibyles and the triangle has three sides

6 0

3 years ago