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lana [24]
3 years ago
15

Screws and wedges are modified blank

Physics
1 answer:
4vir4ik [10]3 years ago
8 0
This is what I know 
<span>Splitting securing A wedge is a triangular shaped tool, a compound and portable inclined plane, and one of the six classical simple machines. </span>
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The international Space Station (ISS) orbits the Earth once every 90 mins at an altitude of 409 km. How high would it have to be
Oksi-84 [34.3K]

It would have to be 36,719 Km high in order to be to be in geosynchronous orbit.

To find the answer, we need to know about the third law of Kepler.

<h3>What's the Kepler's third law?</h3>
  • It states that the square of the time period of orbiting planet or satellite is directly proportional to the cube of the radius of the orbit.
  • Mathematically, T²∝a³
<h3>What's the radius of geosynchronous orbit, if the time period and altitude of ISS are 90 minutes and 409 km respectively?</h3>
  • The time period of geosynchronous orbit is 24 hours or 1440 minutes.
  • As the Earth's radius is 6371 Km, so radius of the ISS orbit= 6371km + 409 km = 6780km.
  • If T1 and T2 are time period of geosynchronous orbit and ISS orbit respectively, a1 and a2 are radius of geosynchronous orbit and ISS orbit, as per third law of Kepler, (T1/T2)² = (a1/a2)³
  • a1= (T1/T2)⅔×a2

           = (1440/90)⅔×6780

           = 43,090 km

  • Altitude of geosynchronous orbit = 43,090 - 6371= 36,719 km

Thus, we can conclude that the altitude of geosynchronous orbit is 36,719km.

Learn more about the Kepler's third law here:

brainly.com/question/16705471

#SPJ4

   

6 0
2 years ago
The dot or scalar product of two (3d) vec- tors ⃗a = ⟨a1,a2,a3⟩ and ⃗b = ⟨b1,b2,b3⟩ is defined as
Neko [114]

Yes, yes, we know all of that.  It certainly took you long enough to
get around to asking your question.

If
     a = (14, 10.5, 0)
and
     b = (4.62, 9.45, 0) ,

then, to begin with, neither vector has a z-component, and they
 both lie in the x-y plane.

Their dot-product  a · b = (14 x 4.62) + (10.5 x 9.45) =

                                             (64.68)   +   (99.225)  =  163.905 (scalar)          


I feel I earned your generous 5 points just reading your treatise and
finding your question (in the last line).  I shall cherish every one of them.                     

7 0
3 years ago
Suppose an electrical wire is replaced with one having every linear dimension doubled (i.e. the length and radius have twice the
saul85 [17]

Answer:

The wire now has less (the half resistance) than before.

Explanation:

The resistance in a wire is calculated as:

R=\alpha \frac{l}{s}

Were:

R is resistance

\alpha is the resistance coefficient

l is the length of the material

s is the area of the transversal wire, in the case of wire will be circular area (s=\pi r^{2}).

So if the lenght and radius are doubled, the equation goes as follows:

R=\alpha \frac{l}{\pi r^{2} } =\alpha \frac{2l}{\pi {(2r)}^{2} } =\alpha \frac{2l}{\pi 4 {r}^{2} }=\frac{1}{2} \alpha \frac{l}{\pi r^{2} }

So finally because the circular area is a square function, the resulting equation is half of the one before.

7 0
3 years ago
The number of players on a regulation Basketball Team?
mixer [17]
Basketball is played with two<span> teams, with </span>4 players<span> from each team on the court at one time. The maximum number of players on the bench differs by league. In international play, a maximum of </span>7 players<span> are allowed on the bench, resulting in a roster of </span>12 players<span>. 

I hope this helps!
</span>
5 0
3 years ago
Read 2 more answers
William Tell shoots an apple from his son's head. The speed of the 102-g arrow just before it strikes the apple is 26.7 m/s, and
xxMikexx [17]

To develop the problem, we require the values concerning the conservation of momentum, specifically as given for collisions.

By definition the conservation of momentum tells us that,m_1V_1+m_2V_2 = (m1+m2)V_f

To find the speed at which the arrow impacts the apple we turn to the equation of time, in which,

t= \sqrt{\frac{2h}{g}}

The linear velocity of an object is given by

V=\frac{X}{t}

Replacing the equation of time we have to,

V_f = \frac{X}{t}\\V_f =\frac{X}{\sqrt{\frac{2h}{g}}}\\V_f = \frac{6.9}{\sqrt{\frac{2(1.85)}{9.8}}}\\V_f = 11.23m/s

Velocity two is neglected since there is no velocity of said target before the collision, thus,

m_1V_1 = (m1+m2)V_f

Clearing for m_2

m_2 = \frac{m_1V_1}{V_f}-m_1\\m_2 = \frac{(0.102)(26.7)}{11.23}-0.102\\m_2 = 0.1405KG= 140.5g

8 0
2 years ago
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