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Jet001 [13]
3 years ago
6

You hold block A with a mass of 1 kg in one hand and block B with a mass of 2 kg in the other. You release them both from the sa

me height above the ground at the same time. (Air resistance can safely be ignored as they fall.) Which of the following describes and explains the motion of the two objects after you release them?
A) Before A hits the ground before the block B. The same force of gravity acts on both objects, but because block A has a lower mass, it will have a larger acceleration
B) Block B hits the ground before the block A. The larger force on block B causes it to have a greater acceleration than block A
C) The two blocks hit the ground at the same time, because they both ackelerate at the same rate while falling. The greater gravitational force on block B is compersated giving it the same acceleration
D) The two blocks hit the ground at the same time because they move at the same constant speed while falling.The force on the blocks are irrelevent once they start falling
Physics
1 answer:
Dominik [7]3 years ago
5 0

ok so im not that good when it comes to physics but i think its C)

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The ball is moving at a constant speed of 0.5 m/s for 2.3 seconds how far does it go?
yarga [219]

Distance = (speed) x (time)

Distance = (0.5 m/s) x (2.3 s)

Distance = (0.5 x 2.3) m

Distance = 1.15 meters

7 0
3 years ago
A 120-kg object and a 420-kg object are separated by 3.00 m At what position (other than an infinitely remote one) can the 51.0-
djverab [1.8K]

Answer:

1.045 m from 120 kg

Explanation:

m1 = 120 kg

m2 = 420 kg

m = 51 kg

d = 3 m

Let m is placed at a distance y from 120 kg so that the net force on 51 kg is zero.

By use of the gravitational force

Force on m due to m1 is equal to the force on m due to m2.

\frac{Gm_{1}m}{y^{2}}=\frac{Gm_{2}m}{\left ( d-y \right )^{2}}

\frac{m_{1}}{y^{2}}=\frac{m_{2}}{\left ( d-y \right )^{2}}

\frac{3-y}{y}=\sqrt{\frac{7}{2}}

3 - y = 1.87 y

3 = 2.87 y

y = 1.045 m

Thus, the net force on 51 kg is zero if it is placed at a distance of 1.045 m from 120 kg.

6 0
3 years ago
Which of the following is a correct definition of radiant energy?
ValentinkaMS [17]
Radiant energy is the energy of electromagnetic and gravitational radiation
6 0
3 years ago
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suppose you got up this morning and the lightbulb in your room wouldn't come on. Use the of the scientific method to explain how
Anna007 [38]

Answer:TEP 1: State the Problem

A problem is a question to be thought about and either solved or answered. Problems surround all of us. Each day we are faced with more problems than we realize and we use the scientific method to solve them without even thinking about it.

EXAMPLE: The lamp does not come on when you flip the switch.

Your problem may be something that you observe around you or it can be determined by researching a topic and attempting to repeat an experiment of another scientist based on what you are working with.

STEP 2: Make Observations

An observation is the act of recognizing and recording something that is happening. Observing often involves the use of measurements and instruments to take measurements with.

EXAMPLE: (1) There is a light bulb. (2) The switch is in the on position.

(3)Other lights in the house are on. (4) The electrical cord is plugged in.

You make these observations based on the things you see, hear, and in other ways notice going on around you. You may also base your observations on information you found from researching the topic. Maybe you found the manual for the lamp and read about how it is supposed to work. You might have searched for information about Thomas Edison and his invention of the light bulb. These works of others are called background research.

 

STEP 3: Form a Hypothesis

A hypothesis is an educated guess meaning an explanation for something that happens based on facts that can then be tested to try and find logical answers.

EXAMPLE: The light bulb is burned out.

Your hypothesis should answer your question of why the lamp does not come on. You can come to this conclusion based on your own knowledge or from researching how a lamp works. We assume that if the lamp is plugged in and turned on that it should light. We also know that if other lights in the house are on, some electricity is running through the house. Your hypothesis does not have to be proven correct by your experiment, it just needs to be testable.

Having more than one hypothesis is fine. There could be a number of reasons why the lamp is not lit and testing them all might be the only way to find an answer. Before beginning to experiment, use logical reason to determine if any of your hypotheses can be eliminated. Maybe the fuse is blown or the outlet is bad. The switch could be wired wrong or broken. These are all testable hypotheses that could be looked into if the light bulb is not the problem.

 

STEP 4: Experiment

An experiment is a step-by-step procedure that is carried out under controlled conditions to attempt to prove a hypothesis, discover and unknown effect or law, or to illustrate a known law.

EXAMPLE: First remove the light bulb and screw it back in tightly to make sure that it was not loose. If that does not work, take the bulb from a lamp you know is working and place it in the broken lamp. If that lights, try another bulb to be sure.

Your experimental set-up should include a control and a variable. You may include more than one variable, but this will increase the size of your experiment. It is also very important to replicate in your experimetal procedure to avoid error. This means that you should try it at least three times. From your experiment you will need to gather data. Data can be organized in charts and or graphs and numerical data should be measured using the metric system.

The Metric System

How To Organize a Data Table

How To Graph

 

STEP 5: Draw a Conclusion

A conclusion is a reasonable judgment based on the examination of data from an experiment. The result or outcome of an act or process.

EXAMPLE: The lamp lit after the bulb was changed, therefore the light bulb must have been burned out.

You might also know from experience that if the filament is broken in a light bulb, it will make a rattling sound when you shake the bulb. To confirm your results, you could shake the bul

Explanation:

5 0
3 years ago
cylindrical container is to be constructed to be open at the top with a volume of 27π cubic meters using the least amount of mat
Llana [10]

Answer:

radius comes out to be 3 m

height of the cylinder comes out to be 3m

Explanation:

given

volume of cylinder = 27π m³

π r² h = 27π

   r² h = 27.............(1)

surface area of cylinder open at the top

S = 2πrh + π r²

S = 2\pi \dfrac{27}{r} + \pi r^2

\frac{\mathrm{d} s}{\mathrm{d} r}=\frac{\mathrm{d}}{\mathrm{d} r} (2\pi \dfrac{27}{r} + \pi r^2)

\frac{\mathrm{d} s}{\mathrm{d} r}=54\pi \dfrac{-1}{r^2}+2\pi r

\frac{\mathrm{d} s}{\mathrm{d} r}=0

for least amount of material requirement.

\dfrac{54\pi }{r^2} = 2\pi r\\r=3m

hence radius comes out to be 3 m

for height put the value in the equation 1

so, height of the cylinder comes out to be 3m

3 0
3 years ago
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