Answer:
= 3.78 g H₂O
Explanation:
2C₂H₆ + 3O₂ => 4CO₂ + 6H₂O
2.1g C₂H₆ = 2.1g/30.0 g/mol = 0.07 mole ethane
3.68g O₂ = 3.68g/32 g/mol = 0.115 mole oxygen
Limiting Reactant:
A quick way to determine limiting reactant is to divide moles of reactant by its respective coefficient in the balanced molecular equation. The smaller value is the limiting reactant.
moles ethane = 0.07 mole / 2 (the coefficient in balanced equation) = 0.035
moles oxygen = 0.115 mole / 3 (the coefficient in balanced equation) = 0.038
Since the smaller value is associated with ethane, then ethane is the limiting reactant and the problem is worked from the 0.07 moles of ethane in an excess of O₂.
From the equation stoichiometry ...
2 moles C₂H₆ in an excess of O₂ => 6 moles H₂O
then 0.07 mole C₂H₆ in an excess of O₂ => 6/2(0.07 moles H₂O = 0.21 mole
Converting to grams of water produced
= 0.21 mole H₂O X 18 g/mol = 3.78 g H₂O
Answer:
The removal of one or more electrons from a neutral atom results in a cation.
Explanation:
When you remove electrons from a neutral atom, the atom becomes more positive. Electrons have a negative charge and the protons inside of the nucleus have a positive charge. When electrons are removed, the positive charges from the protons outweigh the negative charges. This results in a positively charged atom, called a cation.
Answer:
<h2>10.5 gram(cm)^-3 is the right answer.</h2>
The balanced chemical equation for the reaction is as below
KBr (aq) + AgNo3 → KNO3(aq) + AgBr(s)
Explanation
from the equation above the stoichiometric coefficient before KBr is 1, before AgNo3 is 1 , before KNO3 is 1 and before AgBr is also 1. Therefore 1 mole of KBr reacted with 1 mole of AgNO3 to form 1 mole of KNO3 and 1 mole of AgBr.
How many valence electrons are in an atom of phosphorus?
a. 2
c. 4
b. 3
d. 5 Please select the best answer from the choices provided A B C D
There are five valence
electrons are in an atom of phosphorus. The answer is letter D.
